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lubasha [3.4K]
3 years ago
12

How do the data support your claim above?

Chemistry
A12
3 years ago
The data should support your claim by proving that your correct. If your claim can not be supported by your data then you are incorrect.
2 answers:
Ksenya-84 [330]3 years ago
8 0
Is this a question ...
Lana71 [14]3 years ago
7 0

Answer:

bro

Explanation:

oh my gosh

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Select all the true statements regarding chemical equilibrium.
gladu [14]
Chemical equilibrium is reach when the concentrations of the product and reactants will no longer change with time. this does not mean that there is no change in concentration, only the net change is zero. the forward rate of reaction is now equal to backward rate of reaction.
7 0
4 years ago
********WORTH 25 POINTS******What are 3 examples of Chemical weathering?
Scrat [10]

Answer:

Carbonation. When you think of carbonation, think carbon

Oxidation. Oxygen causes oxidation.

Hydration. This isn't the hydration used in your body, but it's similar.

Explanation:

5 0
3 years ago
A.1 B.2 C.3 D.4 Please help!
VashaNatasha [74]
I think its 3 precipitation.
6 0
3 years ago
Read 2 more answers
1) The temperature inside my refrigerator is about 40 Celsius. If I place a balloon in my fridge that initially has a temperatur
viva [34]

Answer:  The volume of the balloon when it is fully cooled by my refrigerator is 0.3 L

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=0.5L\\T_1=220^oC=(220+273)K=493K\\V_2=?\\T_2=40^oC=(40+273)K=313K

Putting values in above equation, we get:

\frac{0.5}{493}=\frac{V_2}{313}\\\\V_2=0.3

Thus the volume of the balloon when it is fully cooled by my refrigerator is 0.3 L

4 0
3 years ago
PLEASE HELP ASAP!!!!
Vsevolod [243]

Answer:

The answer to your question is  C = 0.037 cal/g°C

Explanation:

Data

mass of the wire = m = 237 g

temperature 1 = T1 = 25°C

temperature 2 = T2 = 107°C

Heat = Q = 722 cal

Specific heat = C

Process

1.- Write the formula to find the specific heat

            Q = mC(T2 - T1)

-Solve for C

            C = Q / m(T2 - T1)

2.- Substitution

             C = 722 / 237(107 - 25)

3.- Simplification

              C = 722 / 237(82)

              C = 722 / 19434

4.- Result

               C = 0.037 cal/g°C

4 0
3 years ago
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