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Vlad [161]
3 years ago
9

Required information A plastic beach ball has radius 21.6 cm and mass 0.100 kg, not including the air inside. Assume the air den

sity is 1.30 kg/m3 both inside and outside. What is the weight of the beach ball including the air inside? N.
Physics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

The weight of the ball including the air inside is 1.519 N

Explanation:

First of all, we calculate the volume of the ball, which is the volume of a sphere:

V=\frac{4}{3}\pi r^3

where

r = 21.6 cm = 0.216 m is the radius

Substituting,

V=\frac{4}{3}\pi(0.216)^3=0.042 m^3

Now we can calculate the mass of the air inside the ball, knowing that its density is

\rho = 1.30 kg/m^3

Its mass is

m'=\rho V=(1.30)(0.042)=0.055 kg

We also know that the mass of the ball is

m = 0.100 kg

So the total mass is

M=m+m'=0.100+0.055=0.155 kg

Finally we can calculate the weight:

W=Mg

where g=9.8 m/s^2 is the acceleration of gravity. Substituting,

W=(0.155)(9.8)=1.519 N

Learn more about weight:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

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Two metallic rods A and B of different materials have same length. The linear expansivity of A is 12×10–6 oC–1and cubical expans
uysha [10]

Answer:

The length of rod A will be <u>greater than </u>the length of rod B

Explanation:

We, know that the formula for final length in linear thermal expansion of a rod is:

L' = L(1 + ∝ΔT)

where,

L' = Final Length

L = Initial Length

∝ = Co-efficient of linear expansion

ΔT = Change in temperature

Since, the rods here have same original length and the temperature difference is same as well. Therefore, the final length will only depend upon the coefficient of linear expansion.

For Rod A:

∝₁ = 12 x 10⁻⁶ °C⁻¹

For Rod B:

∝₂ = β₂/3

where,

β₂ = Coefficient of volumetric expansion for rod B = 24 x 10⁻⁶ °C⁻¹

Therefore,

∝₂ = 24 x 10⁻⁶ °C⁻¹/3

∝₂ = 8 x 10⁻⁶ °C⁻¹

Since,

∝₁ > ∝₂

Therefore,

L₁ > L₂

So, the length of rod A will be <u>greater than </u>the length of rod B

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3 years ago
A ball is dropped from a height of 180m- Calculate the velocity of the ball when it strikes the ground
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Answer:

6s , 60mls

Explanation:

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The wave function of a particle in a one-dimensional box of width L is Ψ(x) = Asin(πx/L). If we know the particle must be somewh
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1. In a demonstration, Mr. K stretches a steel wire to a length 1.23 meters and braces both ends so that they are not free to vi
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Answer:

a.241.08 m/s b. 196 Hz c. 392 Hz

Explanation:

a. Determine the speed of waves within the wire.

The frequency of oscillation of the wave in the string, f = nv/2L where n = harmonic number, v = speed of wave in string, L = length of string = 1.23 m.

Since f = 588 Hz which is the 6 th harmonic, n = 6. So, making v subject of the formula, we have

v = 2Lf/n

substituting the values of the variables into v. we have

v = 2 × 1.23 m × 588Hz/6

v = 241.08 m/s

b. Determine the frequency at which the wire will vibrate with the first harmonic wave pattern.

The first harmonic is obtained from f when n = 1,

So, f = v/2L = 241.08 m/s ÷ 1.23m = 196 Hz

c. Determine the frequency at which the wire will vibrate with the second harmonic wave pattern.

The second harmonic f' = 2f = 2 × 196 Hz = 392 Hz

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The area under a velocity-versus-time graph of an object is
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Answer:

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