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3 years ago

The density of octane is 0.700 g/cm3. What is the mass of one liter of octane?

Chemistry

1 answer:

Gelneren [198K]3 years ago

5 0

Answer:

m = 700 g

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Density of octane = 0.700 g/cm³

Volume = 1 L

Mass = ?

Formula:

D=m/v

D= density

m=mass

V=volume

First of all we will convert the volume in cm³ because density is given in g/cm³ unit.

1 L = 1000 cm³

Now we will put the values in formula:

d= m/v

m = v × d

m = 1000 cm³ × 0.700 g/cm³

m = 700 g

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Answer:

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2 years ago

The reaction of aluminum with chlorine gas is shown.

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Answer:

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Explanation:

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2 years ago

Convert 338 L at 63.0 atm to its new volume at standard pressure.

taurus [48]

The new volume at standard pressure of 1 atm is 21294 liters.

Explanation:

Data given:

Initial volume of the gas V1 = 338 liters

initial pressure on the gas P1 = 63 atm

standard pressure as P2 = 1 atm

Final volume at standard pressure V2 =?

The data given shows that Boyle's law equation is to used:

P1V1 = P2V2

rearranging the equation to calculate V2,

V2 = $\frac{P1V1}{P2}$

Putting the values in the equation:

V2 = $\frac{338X63}{1}$

= 21294 L

as the pressure on the gas is reduced to 1 atm the volume of the gas increased incredibly to 21294 litres.

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3 years ago

The coldest temperature ever recorded on Earth was -128.6Â°F (recorded at Vostok Station, Antarctica, on July 21, 1983). Express

Sever21 [200]

Answer : The correct option is, $-89.2^oF\text{ and }183.9K$

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=(^oF-32)\times \frac{5}{9}$

where,

$^oF$ = temperature in Fahrenheit

$^oC$ = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=273.15+^oC$

where,

$K$ = temperature in Kelvin

$^oC$ = temperature in centigrade

As we are given the temperature in Fahrenheit is, -10

Now we have to determine the temperature in degree Celsius.

$^oC=(^oF-32)\times \frac{5}{9}$

$^oC=(-128.6^oF-32)\times \frac{5}{9}$

$^oC=-89.2$

Now we have to determine the temperature in Kelvin.

$K=273.15+^oC$

$K=273.15+(-89.2^oC)$

$K=183.9$

Therefore, the temperature in degree Celsius and Kelvin are, $-89.2^oF\text{ and }183.9K$

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3 years ago

A chemist prepares a solution by adding 422 mg of Co(NO3)2 (MW = 182.94 g/mol ) to a volumetric flask, and then adding water unt

marishachu [46]

Answer:

3.08 × 10⁻³ M

Explanation:

A chemist prepares a solution by adding 422 mg (0.422 g) of Co(NO₃)₂. The moles of solute associated with this mass, considering that the molar mass is 182.94 g/mol, are:

0.422 g × (1 mol/182.94 g) = 2.31 × 10⁻³ mol

The volume of the solution is 750 mL = 0.750 L.

The molarity of Co(NO₃)₂ is:

M = moles of solute / liters of solution

M = 2.31 × 10⁻³ mol / 0.750 L

M = 3.08 × 10⁻³ M

4 0

3 years ago