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marysya [2.9K]
3 years ago
5

Write a balanced half-cell equation for the reaction occurring at the anode. ignore phases in the reaction.

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
7 0

The balanced half-cell equation for the reaction occurring at the anode is  H2 ---> 2H(+) + 2e(-)

E<u>xplanation:</u>

  • The balanced half-cell equation taking place at the anode is explained below
  • The product produced in the reaction in the fuel cell is water.
  • H2 ---> 2H(+) + 2e(-)
  • In the above reaction, the oxidation state of hydrogen switches from 0 to +1.
  • It is becoming oxidized by delivering two electrons at the anode.
  • In the fuel cell, hydrogen molecules get oxidized to hydronium ions.Thus half-reaction is the oxidation reaction.

<u />

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Mg(OH)2 + 2 HBr à MgBr2 + 2 H2O
AnnyKZ [126]

Explanation:

The balanced equation of the reaction is given as;

Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)

1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?

From the reaction;

2 mol of HBr produces 1 mol of  MgBr2

Converting to masses using;

Mass = Number of moles * Molar mass

Molar mass of HBr = 80.91 g/mol

Molar mass of MgBr2 = 184.113 g/mol

This means;

(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2

18.3g would produce x

161.82 = 184.113

18.3 = x

x = (184.113 * 18.3 ) / 161.82 = 20.8 g

2. How many moles of H2O will be produced from 18.3 grams of HBr?

Converting the mass to mol;

Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol

From the reaction;

2 mol of HBr produces 2 mol of H2O

0.226 mol would produce x

2 =2

0.226 = x

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3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?

From the reaction;

2 mol of HBr reacts with 1 mol of Mg(OH)2

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Answer:-

Oxygen gains electrons and is reduced.

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For this reaction the balanced chemical equation is

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