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marysya [2.9K]
3 years ago
5

Write a balanced half-cell equation for the reaction occurring at the anode. ignore phases in the reaction.

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
7 0

The balanced half-cell equation for the reaction occurring at the anode is  H2 ---> 2H(+) + 2e(-)

E<u>xplanation:</u>

  • The balanced half-cell equation taking place at the anode is explained below
  • The product produced in the reaction in the fuel cell is water.
  • H2 ---> 2H(+) + 2e(-)
  • In the above reaction, the oxidation state of hydrogen switches from 0 to +1.
  • It is becoming oxidized by delivering two electrons at the anode.
  • In the fuel cell, hydrogen molecules get oxidized to hydronium ions.Thus half-reaction is the oxidation reaction.

<u />

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Partial pressure O₂ → 2.74 atm

Explanation:

Let's analyse the data given:

Volume → 3L

In the bottle there is a mixture of gases that contains, O₂, N₂ and CO₂.

Total pressure is 4.80 atm

Let's apply the Ideal Gases Law to determine the total moles of the mixture

P . V = n .  R. T

4.80 atm . 3L = n . 0.082 . 273K

n = 4.80 atm . 3L / 0.082 . 273K → 0.643 moles

We apply the concept of mole fraction:

Mole fraction of a gas X = moles of gas X / Total moles

Mole fraction of a gas X = Partial pressure X / Total pressure

In a mixture, sum of mole fraction of each gas = 1

We determine mole fraction of N₂ → 0.230 / 0.643 = 0.357

We determine mole fraction of CO₂ → 0.350 atm / 4.80 atm = 0.0729

1 - mole fraction N₂ - mole fraction CO₂ = mole fraction O₂

1 - 0.357 - 0.0729 = 0.5701 → mole fraction O₂

We replace in the formula: Mole fraction O₂ = Partial pressure O₂ / 4.80 atm

0.5701 . 4.80 atm = Partial pressure O₂ → 2.74 atm

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