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Daniel [21]
3 years ago
11

QUestion 6 and 7

Chemistry
2 answers:
yKpoI14uk [10]3 years ago
8 0

#6: The living organisms in an ecosystem can be divided into three categories: producers, consumers and decomposers. They are all important parts of an ecosystem.

#7: Nature has its own recycling system: a group of organisms called decomposers. Decomposers feed on dead things: dead plant materials such as leaf litter and wood, animal carcasses, and feces. They perform a valuable service as Earth's cleanup crew

HOPE THIS HELPS

Allisa [31]3 years ago
3 0
#7 decompsers eat on the dead. without decomposers dead leaves, dead animals and dead insects would pile up everywhere
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Why is it difficult to accurately represent ammonia and methane on paper?
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Answer:

The correct answer is because the molecular structure.

Explanation:

The difficulty of ammonia and methane to be represented on paper is due to the molecular structure. These compounds have a three-dimensional projection with defined angles. Ammonia presents angles of 109.5º between the atom of Nitrogen and those of Oxygen. The ammonia presents 107.8º between the oxygen atoms.

In the methane molecule, there is 109.5º between the hydrogen molecules and the carbon atom. This results in the need for a 3D representation of the molecule.

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6 0
3 years ago
Which of the following substances is most likely to be a liquid at room temperature?
FromTheMoon [43]

The answer is: hydrogen peroxide, H2O2.

H₂O₂(hydrogen peroxide) is pale blue, clear, inorganic liquid.

It is liquid because hydrogen bonds between molecules.

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8 0
4 years ago
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malfutka [58]
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4 0
3 years ago
I’m confused on this what do I do??
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5 0
3 years ago
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Suppose you have been given the task of distilling a mixture of hexane + toluene. Pure hexane has a refractive index of 1.375 an
miv72 [106K]

Explanation:

The given data is as follows.

         Refractive index of mixture = 1.456

        Refractive index of hexane = 1.375

        Refractive index of toulene = 1.497

Let mole fraction of hexane = x_{1}

and, mole fraction of toulene = x_{2}

Also,        x_{1} + x_{2} = 1

or,            x_{1} = 1 - x_{2}

Hence, calculate the mole fraction of hexane as follows.

        refractive index mixture= mole fraction hexane × ref index hexane + mole fraction toluene × ref index toluene.

              1.456 = (1 - x_{2}) \times 1.375 + x_{2} \times 1.497

               1.456 = 1.375 - 1.375x_{2} + 1.497x_{2}

               0.081 = 0.122x_{2}

                   x_{2} = \frac{0.081}{0.122}

                                = 0.66

Since,     x_{1} = 1 - x_{2}

                          = 1 - 0.66

                          = 0.34

Thus, we can conclude that mole fraction of hexane in your sample is 0.34.        

3 0
4 years ago
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