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kogti [31]
3 years ago
9

You can buy 5 cans for greens beans at the village market for $2.00.

Mathematics
1 answer:
Maslowich3 years ago
8 0

Answer: whats the question here?

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What is the density of water? Remember for water 1g=1ml=1cm^3
NeTakaya

Answer:

1 g/cm^3 or 1 g/ml

Step-by-step explanation:


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3 years ago
Please help me on this it a about to be due
makvit [3.9K]

Answer:

A

Step-by-step explanation:

sin is opposite/hypotenuse, which is 24/26, simplifying to 12/13

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3 years ago
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GETS BRAINILIST!!!!The table shows the relationship between the number of drops of food color added to different number of cups
Kryger [21]

Answer:

I would say the first one

Step-by-step explanation:

A graph is shown. The title of the graph is Cake Decorating. The horizontal axis label is Frosting in cups. The horizontal axis values are 0, 10, 20, 30, 40, 50, 60. The vertical axis label is Food Color in drops. The vertical axis values are 0, 20, 40, 60, 80, 100, 120.

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3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
3 years ago
The hollow sphere has a diameter of 6 cm. Which expressions represent the volume of the shaded composite figure? Check all that
nikklg [1K]

It’s A, C and D. Idk about explanations

6 0
3 years ago
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