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prohojiy [21]
3 years ago
13

Please can you help me with this ​

Chemistry
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

C. Pulley.

Explanation:

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Calculate the molar mass of the following compound: Ca3P2
julia-pushkina [17]

Answer:

The molar mass of the compound given is 182.182 g/mol.

Explanation:

To calculate the molar mass of the compound, we must multiply the number of moles of each element by the the individual molar mass of each element and add them together.

Let's start with Calcium.  The molar mass of Calcium is 40.078.  In this compound, we have three moles of Calcium, so we should multiply this number by 3.

40.078 g/mol * 3 mol = 120.234 g

Now, let's do the same for Phosphorus.

30.974 g/mol * 2 g/mol = 61.948 g

To find the molar mass of the entire compound, we should add these two values together.

120.234 g + 61.948 g = 182.182 g

Therefore, the correct answer is 182.182 g/mol.

Hope this helps!

6 0
3 years ago
How many additional electrons does this atom of oxygen need in its valence shell to satisfy the octet rule?
vfiekz [6]

Answer:

2

Explanation:

cause it is what it is :> mark me brainlest

5 0
4 years ago
What is the main idea of thomas paines the crisis ​
chubhunter [2.5K]

The main idea was that the best thing for the American people to do was to fight for their independence from Great Britain.

8 0
3 years ago
Read 2 more answers
What is the percent by mass of water in MgSO4 • 7H2O? A. 51.1% B. 195% C. 56.0% D. 21.0%
lbvjy [14]

Answer : The correct option is, (A) 51.1%

Explanation :

Mass percent : It is defined as the mass of the given component present in the total mass of the compound.

Formula used :

\text{Mass} \%H_2O=\frac{\text{Mass of }H_2O}{\text{Mass of }MgSO_4.7H_2O}\times 100

First we have to calculate the mass of H_2O and MgSO_4.7H_2O.

Mass of H_2O = 18 g/mole

Mass of 7H_2O = 7 × 18 g/mole = 126 g/mole

Mass of MgSO_4.7H_2O = 246.47 g/mole

Now put all the given values in the above formula, we get the mass percent of H_2O in MgSO_4.7H_2O.

\text{Mass} \%H_2O=\frac{126g/mole}{246.47g/mole}\times 100=51.1

Therefore, the mass percent of H_2O in MgSO_4.7H_2O is, 51.1%

6 0
3 years ago
Give reasons.<br> a.Steel is an alloy.<br> b.Sodium is a metal.
JulsSmile [24]

Answer:

  1. <em>stee</em><em>l</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>allo</em><em>y</em><em> </em><em>because</em><em> </em><em>steel</em><em> </em><em>when</em><em> </em><em>oth</em><em>er</em><em> </em><em>ele</em><em>ments</em><em> </em><em>compri</em><em>sing</em><em> </em><em>metals</em><em> </em><em>and</em><em> </em><em>n</em><em>o</em><em>n</em><em>metals</em><em> </em><em>a</em><em>re</em><em> </em><em>adde</em><em>d</em><em> </em><em>to</em><em> </em><em>Carbon</em><em> </em><em>ste</em><em>el</em><em> </em><em>,</em><em> alloy</em><em> </em><em>ste</em><em>el</em><em> </em><em>is</em><em> </em><em>for</em><em>med</em><em>.</em>
  2. <em>Sodi</em><em>um</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>meta</em><em>l</em><em> </em><em>beca</em><em>use</em><em> </em><em>it</em><em> </em><em>i</em><em>s</em><em> </em><em>hi</em><em>ghly</em><em> </em><em>reactive</em><em> </em><em>metal</em><em>.</em><em>i</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>the</em><em> </em><em>memb</em><em>er</em><em> </em><em>of</em><em> </em><em>alkali</em><em> </em><em>me</em><em>tal</em><em> </em><em>fami</em><em>ly</em><em> </em><em>abo</em><em>ut</em><em> </em><em>the</em><em> </em><em>perio</em><em>dic</em><em> </em><em>table</em><em> </em><em>.</em><em>it</em><em> </em><em>has</em><em> </em><em>one</em><em> </em><em>electron</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>outer</em><em>most</em><em> </em><em>electron</em><em> </em><em>shel</em><em>l</em><em>.</em>

Explanation:

Hope it's help !

4 0
3 years ago
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