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3 years ago

The graphics below shows how photosynthesis and cellular respiration are related.

Chemistry

1 answer:

lisov135 [29]3 years ago

8 0

Options found from another source are:

a. oxygen. b. glucose. c. energy stored as ATP. d. carbon dioxide and water

Answer:

c energy stored as ATP

Explanation:

Cellular respiration converts glucose into energy in the form of ATP (c). The answer cannot be oxygen (a), because this is required for this process as a final electron acceptor. In terms of photosynthesis, oxygen is released as a by-product. The answer cannot be glucose (b) because that is our starting point for respiration, and what is synthesised during photosynthesis. The answer cannot be (d) as carbon dioxide and water are released by cellular respiration, and required by photosynthesis

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Which of the following chemical formulas show three molecules of a compound that has one

mr_godi [17]

The chemical formula : 3HgBr₂(Mercury(II) bromide)

<h3>Further explanation</h3>

Given

The chemical formulas of Mercury and Bromine

Required

The appropriate chemical formula

Solution

A molecular formula is a formula that shows the number of atomic elements that make up a compound.

The number of molecules is determined by the coefficient in front of the compound

the number of atoms is determined by the subscript after the atom and the coefficient

Three molecules⇒ coefficient = 3

one atom of Mercury ⇒Hg

two atoms of Bromine ⇒ Br₂

The chemical formula : 3HgBr₂

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2 years ago

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ZanzabumX [31]

Answer:

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3 years ago

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How many moles of copper are present in a sample that contains 4.55 x 10^24 atoms of copper

FinnZ [79.3K]

Hope you could understand.

If you have any query, feel free to ask.

3 0

2 years ago

The particles of a gas are<br> O electrons<br> O atoms or molecules<br> O neutrons<br> O waves

Harrizon [31]

Answer:
atoms or molecules

Explanation:
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8 0

2 years ago

Calculate the energy, in joules, required to ionize a hydrogen atom when its electron is initially in the n =2 energy level. The

qaws [65]

Answer:

$E_{ionization}=5.45\times 10^{-19}\ J$

Explanation:

$E_n=-2.18\times 10^{-18}\times \frac{1}{n^2}\ Joules$

For transitions:

$Energy\ Difference,\ \Delta E= E_f-E_i =-2.18\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

$\Delta E=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

So, $n_i=2$ and $n_f=\infty$ (As the hydrogen has to ionize)

Thus,

$\Delta E=2.18\times 10^{-18}(\frac{1}{2^2} - \dfrac{1}{{\infty}^2})\ J$

$\Delta E=2.18\times 10^{-18}(\frac{1}{2^2})\ J$

$E_{ionization}=5.45\times 10^{-19}\ J$

4 0

3 years ago