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OLEGan [10]
4 years ago
11

1) In what state or phase do most ionic compounds occur? A) Solid. B) Liquid. C) Gas. D) Plasma. 2) The compound CO is an exampl

e of a(n). A) salt. B) element. C) ionic compound. D) covalent compound.
Chemistry
1 answer:
ELEN [110]4 years ago
3 0
1)The state or phase in which most ionic compounds occur will be a solid state or phase. This will make the correct answer A. 

2) The compound Co is an example of a covalent compound. This will make the answer to be D. 
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Why are infants and children often more susceptible to the effects of toxic substances than adult? (Explain)
puteri [66]

From what I know personally from learning about this type of subject in the past is that children are more susceptible to the effects of toxic substances more than adults are, certain scientific data specifically indicate that children actually are for all intents and purposes more basically susceptible to toxic exposure than adults because they for the most part have proportionally definitely more intake of food contaminants, basically active developmental processes, basically multiple exposure pathways and really susceptible kind of socio-behavioral activities in a particularly major way.

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3 years ago
How would you prepare 250 mL of a 0.100 M solution of fluoride ions<br> from solid CaF2?
andrey2020 [161]

In 250 mL of volumetric flask add 0.975875 grams of CaF_2 and dissolve it in the 250 mL of water.

Given:

The solid of calcium fluoride.

To prepare:

The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.

Method:

Molarity of the fluoride ion solution needed = M = 0.100 M

The volume of the fluoride ion solution needed = V = 250 mL

1 mL = 0.001L\\V=250 mL=250\times 0.001 L=0.250 L

The moles of fluoride ion needed = n

According to the definition of molarity:

M=\frac{n}{V}\\0.100M=\frac{n}{0.250 L}\\n=0.100M\times 0.250 L=0.025 mol

Moles of fluoride ion = 0.025 mol

We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.

CaF_2(s)\rightarrow Ca^{2+}(aq)+2F^-(aq)

According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:

=\frac{1}{2}\times 0.025 mol=0.0125 \text{mol of } CaF_2

Moles of calcium fluoride = 0.0125 mol

Mass of calcium fluoride needed to prepare the solution :

=0.0125 mol\times 78.07 g/mol=0.975875 g

Preparation:

  • Weight 0.975875 grams of calcium fluoride
  • Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
  • Now add a small amount of water to dissolve the calcium fluoride completely.
  • After this add more water up to the mark of the volumetric flask of volume 250 mL.

Learn more about molarity of solution ere:

brainly.com/question/10053901?referrer=searchResults

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Does anyone know what convection,conduction,radiation??
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