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Lelechka [254]
3 years ago
6

Write a balanced equation for the ionization of hydrochloric acid in water. Assume that hydronium ion is formed. (Use the lowest

possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)
Chemistry
1 answer:
Svetllana [295]3 years ago
3 0

Answer:

HCl(g) + H₂O(l) -> Cl⁻(aq) + H₃O⁺(aq)

Explanation:

Usually when we have HCl in a lab, it's already dissolved in water. It's just HCl(aq). If we want to look at adding pure HCl, that'll be a gas. We should note that HCl is a strong acid that will break apart completely. One might not say that this is a chemical reaction so much as a dissociation. Strong acids are proton donors and form hydronium cations in aqueous solution.

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How many moles of NaCl are present in 2.50 L of a 0.070 M solution?
posledela

Given :

Volume of NaCl solution 2.5 L .

Molarity of NaCl solution is 0.070 M .

To Find :

How many moles are present in the solution.

Solution :

Let, n be the number of moles.

We know, molarity is given by :

M = \dfrac{n}{V(in\ L)}

So,

n = M \times V\\\\n = 0.070\times 2.5 \\\\n = 0.175\ moles

Therefore, number of moles of NaCl is 0.175 moles.

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Carbon diselenide (CSe2) is a liquid at room temperature. The normal boiling point is 125°C, and the melting point is –45.5°C. C
Tema [17]

Answer:

Explanation:  The strengths of the inter molecular forces varies as follows -

        CO_{2}< CS_{2} < CSe_{2}

The normal boiling point of CSe2 is 125°C and that of CS2 is 116°C, which explains the trend that as we move down the group, the boiling point of e compound increases as the size increases.

This usually happens because larger and heavier atoms have a tendency to exhibit greater inter molecular strengths due to the increase in size . As the size increases, the valence shell electrons move far away from the nucleus, thus has a greater tendency to attract the temporary dipoles.

And larger the inter molecular forces, more tightly the electrons will be held to each other and thus more thermal energy would be required to break the bonds between them.

5 0
3 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
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