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Nesterboy [21]
3 years ago
12

You need to prepare 250. ml of a 0.600 m aqueous solution of sucrose, c12h22o11(aq, which is used frequently in biological exper

iments.
Chemistry
1 answer:
Darya [45]3 years ago
6 0
Molality is a unit of measurement for concentration that is calculated through the equation,
                               m  = moles of solute / kg of solvent
Recall that because water's density is approximately equal to 1 g/mL, 250 mL of water is also equal to 250 g or 0.25 kg. Substituting the known values,
                            0.6 = moles of solute / 0.25 kg solvent
                        moles of solute = 0.15 moles
Then, we determine the mass of sucrose by multiplying the calculated number of moles with the molar mass of sucrose (342 g/mol). The answer would be equal to 51.3 g. 
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The colour of light depends on it's wave length.Red light have a wave length in the order of 7.8*10 raise to power of -7metre, e
Arisa [49]
That will be 0.78*10 raise to the power of -1 nanometers
8 0
3 years ago
Consider the following reaction where Kc = 1.80×10-2 at 698 K:
Klio2033 [76]

Answer:

The system is not in equilibrium and the reaction must run in the forward direction to reach equilibrium.

Explanation:

The reaction quotient Qc is a measure of the relative amount of products and reagents present in a reaction at any given time, which is calculated in a reaction that may not yet have reached equilibrium.

For the reversible reaction aA + bB⇔ cC + dD, where a, b, c and d are the stoichiometric coefficients of the balanced equation, Qc is calculated by:

Qc=\frac{[C]^{c}*[D]^{d}  } {[A]^{a}*[B]^{b}}

In this case:

Qc=\frac{[H_{2} ]*[I_{2} ] } {[HI]^{2}}

Since molarity is the concentration of a solution expressed in the number of moles dissolved per liter of solution, you have:

  • [H_{2} ]=\frac{2.09*10^{-2} moles}{1 Liter}=2.09*10⁻² \frac{moles}{liter}
  • [I_{2} ]=\frac{4.14*10^{-2} moles}{1 Liter}=4.14*10⁻² \frac{moles}{liter}
  • [I_{2} ]=\frac{0.280 moles}{1 Liter}= 0.280 \frac{moles}{liter}

So,

Qc=\frac{2.09*10^{-2} *4.14*10^{-2}  } {0.280^{2} }

Qc= 0.011

Comparing Qc with Kc allows to find out the status and evolution of the system:

If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.

If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

Being Qc=0.011 and Kc=1.80⁻²=0.018, then Qc<Kc. <u><em>The system is not in equilibrium and the reaction must run in the forward direction to reach equilibrium.</em></u>

8 0
3 years ago
69. Sequencing Arrange these hydrates in order of
Kobotan [32]

In order of  increasing percent water content:CoCl₂.6H₂O, Ba(OH)₂.8H₂O, MgSO₄.7H₂O

<h3>Further explanation</h3>

\tt \%element=\dfrac{Ar~element}{MW~compound}\times 100\%

CoCl₂.6H₂O.MW=237.90 g/mol

6H₂O MW = 6.18=108 g/mol

\tt \%H_2O=\dfrac{108}{237.9}\times 100\%=45.4\%

MgSO₄.7H₂O.MW=246.48 g/mol

MW 7H₂O = 7.18=126 g/mol

\tt \%H_2O=\dfrac{126}{246.48}\times 100\%=51.1\%

Ba(OH)₂.8H₂O MW=315.48 g/mol

MW 8H₂O = 8.18=144 g/mol

\tt \%H_2O=\dfrac{144}{315.48}\times 100\%=45.6\%

4 0
3 years ago
Calculate the molar mass of each of the following:
Allushta [10]

Explanation:

Molar mass

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

(a) S₈

Molar mass of of the atoms are -

sulfur, S = 32 g/mol.

Molar mass of  S₈ = 8 * 32 g/mol.  = 256 g/mol.

(b) C₂H₁₂

Molar mass of of the atoms are -

Hydrogen , H = 1 g/mol

Carbon , C = 12 g/mol

Molar mass of C₂H₁₂ = ( 2 * 12 ) + (12 * 1 ) = 36 g /mol

(c) Sc₂(SO₄)₃

Molar mass of of the atoms are -

sulfur, S = 32 g/mol.

oxygen , O = 16 g/mol.

scandium , Sc = 45 g/mol.

Molar mass of Sc₂(SO₄)₃ = (2 * 45 ) + ( 3 *32 ) + ( 12 * 16 ) = 378 g /mol  

(d) CH₃COCH₃ (acetone)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol

oxygen , O = 16 g/mol.

Hydrogen , H = 1 g/mol

Molar mass of CH₃COCH₃ (acetone) = (3 * 12 ) + ( 1 * 16 ) + ( 6 * 1 ) = 58g/mol

(e) C₆H₁₂O₆ (glucose)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol

oxygen , O = 16 g/mol.

Hydrogen , H = 1 g/mol

Molar mass of C₆H₁₂O₆ (glucose) = ( 6 * 12 ) + ( 12 * 1 ) + ( 6 * 16 ) = 108g/mol.

6 0
3 years ago
Solid aluminum metal reacts with aqueous zinc chloride to produce solid zinc metal and aqueous aluminum chloride
yuradex [85]

Answer:

2Al + 3ZnCl₂    →    3Zn + 2AlCl₃

Explanation:

Chemical equation:

Al + ZnCl₂    →    Zn + AlCl₃

Balanced Chemical equation:

2Al + 3ZnCl₂    →    3Zn + 2AlCl₃

This is the example of single displacement reaction. Al displace the zinc and form aluminium chloride and zinc metal.

There are two Al three zinc and six chlorine atoms on both side of equation so it is correctly balanced.

Thus it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

7 0
3 years ago
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