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Nesterboy [21]
4 years ago
12

You need to prepare 250. ml of a 0.600 m aqueous solution of sucrose, c12h22o11(aq, which is used frequently in biological exper

iments.
Chemistry
1 answer:
Darya [45]4 years ago
6 0
Molality is a unit of measurement for concentration that is calculated through the equation,
                               m  = moles of solute / kg of solvent
Recall that because water's density is approximately equal to 1 g/mL, 250 mL of water is also equal to 250 g or 0.25 kg. Substituting the known values,
                            0.6 = moles of solute / 0.25 kg solvent
                        moles of solute = 0.15 moles
Then, we determine the mass of sucrose by multiplying the calculated number of moles with the molar mass of sucrose (342 g/mol). The answer would be equal to 51.3 g. 
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The value for ψ in root tissue was found to be -1.6 bars. If you place the root tissue in a 0.1 m solution of sucrose at 20°c in
Allisa [31]

Answer:

\Psi=\Psi_s+\Psi_p\\

I=1;C=0.1;R=0.0831\\

T=20+273=293~C\\

as beaker is open so

\Psi_p=0\\

\Psi=\Psi_s\\\Psi=-2.43483

As ψof solution is lower than the root tissue so water will move out of the root to the solution

Explanation:

8 0
4 years ago
The energy driving a windmill each minute equals 2.75 kilojoules. If 1.6 kilojoules of energy is given up by the windmill as the
saveliy_v [14]
The answer would be 1.15 kilojoules. ope this helps.
7 0
3 years ago
Oxalic acid is a diprotic acid. calculate the percent of oxalic acid (h2c2o4) in a solid given that a 0.7984-g sample of that so
vlada-n [284]
This method of quantitative determination of percent purity is titrimetric reactions. These reactions most commonly involve neutralization reactions between an acid and a base. Then, we look at the neutralization reaction:

H₂C₂O₄ + 2 NaOH ⇒ Na₂C₂O₄ + 2 H₂O

So, we do the stoichiometric calculations. The important data we should know is the molar mass of oxalic acid which is equal to 90 g/mol.

(0.2283 mol/L NaOH * 0.3798 L * 1 mol H₂C₂O₄/ 2mol NaOH * 90 g/mol H₂C₂O₄) ÷ 0.7984 g *100%
= 488%

This is impossible. The purity can't be more than 100%. Looking at our calculations and the balance reaction, all steps were done correctly. So, I think there is some typographical error in the given. The mass of the sample should be 7.984 g. Then, the answer would be 48.87% purity.
5 0
3 years ago
Read 2 more answers
Can you plss help me in this question​
Rashid [163]

Answer:

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7 0
3 years ago
If an electron gains energy what may happen to it
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It could get bigger or it could have something a lot different to it than anything else
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3 years ago
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