<em>Calculate the pH of the following substances formed during a volcanic eruption: </em>
<em>• Acid rain if the [H +] is 1.9 x 10-5 </em>
<em>• Sulfurous acid if [H +] = 0.10 </em>
<em>• Nitric acid if [H +] = 0.11</em>
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<h3>Further explanation </h3>pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.
pH = - log [H⁺]
Answer:
Explanation:
Hello,
In this case, since the chemical reaction is:
We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:
In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:
Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:
Then, since the concentration and the volume define the moles, we can write:
Therefore, the neutralized volume turns out:
Best regards.