When Phosphoric Acid behaves according to arrhenius theory in water, what are the two products formed by the first proton

Chemistry

1 answer:

bagirrra123 [75]3 years ago

5 0

Answer:

Phosphoric acid is a triprotic acid. This means that it can dissociate in water up to three times, each time releasing a proton into the water as shown in the following reactions:

H3PO4 (s) + H2O (l) is in equilibrium with H3O + (aq) + H2PO4− (aq)

H2PO4− (aq) + H2O (l) is in equilibrium with H3O + (aq) + HPO42− (aq)

HPO42− (aq) + H2O (l) is in equilibrium with H3O + (aq) + PO43− (aq)

Explanation:

Phosphoric acid having contact with water, dissociating from a proton up to three times, that is why the three possible reactions are determined above.

This acid is an acid that belongs to oxo acids and its formula is H3PO4

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3 years ago

You are instructed to create 900. mL of a 0.29 M phosphate buffer with a pH of 7.8. You have phosphoric acid and the sodium salt

Aleksandr [31]

Answer:

B and C

Explanation:

When we have to do a buffer solution we always have to choose the reaction that has the pKa closer to the desired pH value. When we find the pKa values we will obtain:

$pKa_1=-Log[6.9x10^-^3]=2.16$

$pKa_2=-Log[6.2x10^-^8]=7.20$

$pKa_3=-Log[4.8x10^-^13]=12.31$

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