C4h10+6.5o2=4co2+5h2o
moles of butane=1.92/58=0.0331 moles
moles of water=0.1655 moles\
as the butane and water has 1 is to 5 molar ratio
0.1655=mass/18
mass=2.98 g
mass of water produced = 2.98 g
Answer:
5.55 L
Explanation:
This excersise can be solved by the Boyle's law.
This law for gases states that the pressure of a gas in a vessel is inversely proportional to the volume of the vessel.
P₁ . V₁ = P₂ . V₂
The law comes from the Ideal Gases Law, in the first term.
P . V = n . R . T In this case, n . R . T are all constant.
6.35 L . 88.6 kPa = 101.3 kPa . V₂
V₂ = (6.35 L . 88.6 kPa) / 101.3 kPa
V₂ = 5.55 L
It is inversely proportional because, as it happened in this case, pressure was increased, therefore volume decreased.
Answer:
c is the answer
step by step explanation is not
Given :
Number of molecules of
.
To Find :
How many moles are in given number of molecules.
Solution :
We know, in 1 moles of any element/compound contains
at atoms/molecules.
So, number of moles in
molecules are :

Therefore, number of moles are 8.97 .
Answer:
Q = 143,921 J = 143.9 kJ.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the absorbed heat by considering this is a process involving sensible heat associated to the vaporization of water, which is isothermic and isobaric; and thus, the heat of vaporization of water, with a value of about 2259.36 J/g, is used as shown below:

Thus, we plug in the mass and the aforementioned heat of vaporization of water to obtain the following:

Regards!