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Vaselesa [24]
2 years ago
13

The following question appears on a quiz: "You fill a tank with gas at 60°C to 100 kPa and seal it. You decrease the temperature

to 10°C but keep the volume constant. What happens to the pressure?" A student answers that the new pressure will be 17 kPa. Which of the following explanations is true?
The student did not solve for the correct parameter, and the answer should be 50 kPa.

The student did not solve for the correct parameter, and the answer should be 600 kPa.

The student did not work with absolute temperatures, and the answer should be 85 kPa.

The student did not work with absolute temperatures, and the answer should be 888 kPa.
Chemistry
2 answers:
natta225 [31]2 years ago
6 0

The student did not work with absolute temperatures, and the answer should be 85 kPa.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and V are constant, and have two different values of P and T:

P₁T₂ = P₂T₁

P₁ = 100.0 kPa, T₁ = 60.0°C + 273 = 333.0 K.

P₂ = ??? kPa, T₂ = 10.0°C + 273 = 283.0 K.

∴ P₂ = P₁T₂/T₁ = (100.0 kPa)(283.0 K)/(333.0 K) = 84.98 kPa ≅ 85.0 kPa.

So, the right choice is:

The student did not work with absolute temperatures, and the answer should be 85 kPa.

Vilka [71]2 years ago
3 0

Answer:

The student did not work with absolute temperatures, and the answer should be 85 kPa.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and V are constant, and have two different values of P and T:

<em>P₁T₂ = P₂T₁</em>

<em></em>

P₁ = 100.0 kPa, T₁ = 60.0°C + 273 = 333.0 K.

P₂ = ??? kPa, T₂ = 10.0°C + 273 = 283.0 K.

<em>∴ P₂ = P₁T₂/T₁ </em>= (100.0 kPa)(283.0 K)/(333.0 K) = <em>84.98 kPa ≅ 85.0 kPa.</em>

<em></em>

  • So, the right choice is:

<em>The student did not work with absolute temperatures, and the answer should be 85 kPa.</em>

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An electric range burner weighing 699.0 grams is turned off after reaching a temperature of 482.0°C, and is allowed to cool down
jasenka [17]

Answer:

0.42 J/gºC

Explanation:

We'll begin by calculating the heat energy used to heat up the water. This can be obtained as follow:

Mass (M) of water = 560 g

Initial temperature (T₁) = 22.7 °C

Final temperature (T₂) = 80.3 °C.

Specific heat capacity (C) of water = 4.18 J/gºC

Heat (Q) absorbed =?

Q = MC(T₂ – T₁)

Q = 560 × 4.18 (80.3 – 22.7)

Q = 2340.8 × 57.6

Q = 134830.08 J

Finally, we shall determine the specific heat capacity of the burner. This can be obtained as follow:

Mass (M) of burner = 699 g

Initial temperature (T₁) = 482.0°C

Final temperature (T₂) = 22.7 °C

Heat (Q) evolved = – 134830.08 J

Specific heat capacity (C) of the burner =?

Q = MC(T₂ – T₁)

–134830.08 = 699 × C (22.7 – 482.0)

–134830.08 = 699 × C × –459.3

–134830.08 = –321050.7 × C

Divide both side by –321050.7

C = –134830.08 / –321050.7

C = 0.42 J/gºC

Therefore, the specific heat capacity of the burner is 0.42 J/gºC

8 0
2 years ago
How many atoms are there in 3.559*10^-6 mol of krypton?
algol [13]

Answer:

The answer is

<h2>2.143 \times  {10}^{18}  \:  \: atoms</h2>

Explanation:

To find the number of atoms given the number of moles we use the formula

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 3.559 \times  {10}^{ - 6}  \: mol

Substitute the values into the above formula and solve

That's

<h3>N  = 3.559 \times  {10}^{ - 6}  \times 6.02 \times  {10}^{23}  \\  = 2.1425 \times  {10}^{18}</h3>

We have the final answer as

<h3>N  = 2.143 \times  {10}^{18}  \:  \: atoms</h3>

Hope this helps you

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Answer:

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