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2 years ago

What type of molecules interact with water polar or nonpolar

Chemistry

1 answer:

vaieri [72.5K]2 years ago

5 0

Answer:

Polar molecules interact with water

Explanation:

Regarding polarity, molecules interact with substances that have a similar polarity to their own, in other words, polar molecules interact with other polar substances and nonpolar molecules interact with other nonpolar substances.

Because of the electronegativity difference between O and H, water (H₂O) is polar, so it will interact with polar molecules.

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Which substance can not be decomposed by a chemical change?

max2010maxim [7]

B. Copper since the rest of the choices are compounds. Copper is an element.

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2 years ago

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Estimate the enthalpy change for the combustion of one mole of acetylene, C2H2, to form carbon dioxide and water vapor. BE(C?H)

tia_tia [17]

Answer:

ΔH rxn = -1010 kJ/molC₂H₂

Explanation:

To obtain the enthalpy change for a reaction from bond energies what we do is to make an inventory of the bonds broken and formed for the balanced chemical reaction:

C₂H₂ + 5/2O₂ ⇒ 2CO₂ + H₂O

Bond Broken Bonds Formed

2 C-H + 1 C≡C + 5/2 O=O 4C=O + 2 H-O

Enthalpy bonds broken:

2 mol (456 kJ/mol)+ 1 mol (962 kJ/mol) + 5/2 mol (499 kJ/mol) = 3121.5 kJ

Enthalpy bond formed:

4 mol (802 kJ/mol) + 2 mol (462 kJ/mol) = 4132.0 kJ

ΔH rxn = H broken - H formed = 3121.5 kJ - 4132.0 kJ = - 1010 kJ (per mol C₂H₂ )

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2 years ago

PLEASEEE HELPPP MEEE

andrezito [222]

Answer:

yes the one that is circled is correct

Explanation:

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2 years ago

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We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to

andreyandreev [35.5K]

Answer: The correct answer is Option 5.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

$M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of the NaOH.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of the $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL$

Putting all the values in above equation, we get:

$M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M$

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base.

We are given:

$n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL$

Putting values in above equation, we get:

$1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M$

Hence, the correct answer is Option 5.

7 0

3 years ago

Which experimental setup would let a student investigate the connection between kinetic energy and temperature? (1 point) placin

Maslowich

Answer:

The correct option is;

Placing one drop of food coloring in a cup with 60 ml of water at 10°, placing one drop of food coloring in a second cup with 60 ml of water at 40°C

Explanation:

The experimental setup that would allow the student investigate the connection between kinetic energy and temperature should be made up of the following characteristics

1) The constant terms for the experiment should be defined, which in this case are

a) The volume of the water which is 60 ml in both subjects of the experiment

2) The definition of the variable that produces the effect that is being monitored, which is the use of the different temperatures in the two experimental subjects

3)The environmental limits of the experiment, which is the water and the food coloring used

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2 years ago