The question is incomplete,the complete question :
Calculate the molality of a 10.0% (by mass) aqueous solution of hydrochloric acid:
a) 0.274 m
b) 2.74 m
c) 3.05 m
d) 4.33 m
e) the density of the solution is needed to solve the problem
Answer:
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
Explanation:
10.0% (by mass) aqueous solution of hydrochloric acid.
10 grams of HCl is present in 100 g of solution.
Mass of HCl = 10 g
Mass of solution = 100 g
Mass of solution = Mass of solute + Mass of water
Mass of water = 100 g - 10 g = 90 g
Moles of HCl = 
Mass of water in kilograms = 0.090 kg
Molality = 
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
Mg+alcl3-->mgcl2+al is the
Answer: 0.035 moles FeF3 or 3.5x10-² moles FeF3
Explanation: 1 mole of FeF3 is equal to its molar mass ( 113g FeF3)
4.0g FeF3 x 1 mole FeF3 / 113 g FeF3 = 0.035 moles of FeF3
Answer:
If any atom has more electrons than one energy level can hold, then automatically the electron is accommodated in the next energy level (shell). The remaining extra electrons starts to fill the next energy level. This produces the valency of that particular atom.
Explanation:
Answer:
Cystic fibrosis (CF) is a genetic disease that causes thick, sticky mucus to build up in organs, including the lungs and the pancreas. In a healthy person, mucus that lines organs and body cavities, such as the lungs and the nose, is slippery and watery. In people with CF, thick mucus clogs causes symptoms in the lungs and pancreas.
Explanation:
The causes of CF
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