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Step-by-step explanation:
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Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
The rate in
given that riya applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space.
we already know that 1m = 100cm.
so, each side of this cube is 100cm in length.
so,
To find what is the volume in cubic metres.
so, the rate is
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Question : Riya is applying mulch to her garden.She applies it at a rate of 250,000 cm^3 of mulch for every m^2 of garden space. At what rate is riya applying mulch in m^3/m^2