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mash [69]
4 years ago
13

at a 200 meter swimming competition bill got a personal record of 45 secomda and time was 5 secomds faster then bill at the comp

etition what was the speed of time for the swimmimg competition
Physics
1 answer:
steposvetlana [31]4 years ago
4 0

Answer:

Average speed of the swimmer is 4.44 m/s

Explanation:

As we know that the speed is the ratio of distance covered over time interval

so here we can say

v = \frac{d}{t}

so we know that

d = 200 m

time taken to complete the trip is

t = 45 s

now we have

v = \frac{200}{45}

v = 4.44 m/s

You might be interested in
An initially stationary electron is accelerated by a uniform 640 N/C Electric Field. a) Calculate the kinetic energy of the elec
bulgar [2K]

Answer:

(a) 1.298 * 10^(-4) J

(b) 5.82 * 10^6 m/s

Explanation:

Parameters given:

Electric field, E = 640 N/C

Distance traveled by electron, r = 15 cm = 0.15 m

Mass of electron, m = 9.11 * 10^(-31) kg

Electric charge of electron, q = 1.602 * 10^(-19) C

(a) The kinetic energy of the electron in terms of Electric field is given as:

K = (q² * E² * r²) / 2m

Therefore, Kinetic energy, K, is:

K = [(1.602 * 10^(-19))² * 640² * 0.15²] / [2 * 9.11 * 10^(-31)]

K = {23651.981 * 10^(-38)} / [18.22 * 10^(-31)]

K = 1298.13 * 10^(-7) J = 1.298 * 10^(-4) J

(b) To find the final velocity of the electron, we have to first find the acceleration of the electron. This can be gotten by using the equations of force.

Force is generally given as:

F = ma

Electric force is given as:

F = qE

Therefore, equating both, we have:

ma = qE

a = (qE) / m

a = (1.602 * 10^(-19) * 640) / (9.11 * 10^(-31))

a = 112.54 * 10^(12) m/s² = 1.13 * 10^(14) m/s²

Using one of the equations of motion, we have that:

v² = u² + 2as

Since the electron started from rest, u = 0 m/s

Therefore:

v² = 2 * 1.13 * 10^(14) * 0.15

v² = 3.39 * 10^(13)

v = 5.82 * 10^6 m/s

The velocity of the electron after moving a distance of 15 cm is 5.82 * 10^6 m/s.

8 0
3 years ago
A 0.18-kg turntable of radius 0.32 m spins about a vertical axis through its center. A constant rotational acceleration causes t
borishaifa [10]

Answer:

Angular acceleration will be 18.84rad/sec^2

Explanation:

We have given that mass m = 0.18 kg

Radius r = 0.32 m

Initial angular velocity \omega _i=0rev/sec

And final angular velocity \omega _f=24rev/sec

Time is given as t = 8 sec

From equation of motion

We know that \omega _f=\omega _i+\alpha t

24=0+\alpha \times 8

\alpha =3rev/sec^2=3\times 2\times \pi rad/sec^2=18.84rad/sec^2

So angular acceleration will be 18.84rad/sec^2

4 0
4 years ago
You spy on an anchor on the bottom of a lake. What is the direction and amount of force the water exerts on it: a) zero
vaieri [72.5K]

Answer:

c) up, less than the weight of the anchor

Explanation:

An object floats when the weight of the water the object displaces is equal to the weight of the object. In this case the weight of the anchor and the weight of the water it displaces is not the same so it sinks. Buoyancy is the force that acts on body when it is in water.

When buoyancy is less than the force that the object is generating due to gravity the object sinks. Buoyancy always acts up.

5 0
3 years ago
According to special relativity, in which frames of reference does light in a vacuum travel at less than 3.0 108 m/s?
ch4aika [34]
The correct option is D.
According to special relativity, in no frame of reference does light in a vacuum travel at less than the speed of light, the speed of light in a vacuum is the same for any inertial reference frame.This fact remain valid no matter the speed of a light source relative to another observer.
6 0
3 years ago
Read 2 more answers
A person travels by car from one city to an-
Mademuasel [1]
<h2>Answer:</h2>

<h2>Explanation:</h2>

First, let's refer to the distance formula:

d=v*t, where d is distance, v is velocity or speed and t is time.

Now, let's find the distance covered by each individual speed that the car had:

<h3>1. Speed 1.</h3>

In order to use the formula, we need to convert minutes into hours since the speed is given in km/h.

21.1 min/60= 0.35 h.

Now, apply the distance formula.

d=(0.35h)*(86.8km/h)= 30.38 km.

<h3>2. Speed 2.</h3>

Convert minutes to hours again and do the same calculations.

10.6min/60=0.18h

d=(0.18h)*(106km/h)= 19.08 km.

<h3>3. Speed 3.</h3>

36.5min/60= 0.61h

d=(0.61h)*(30.9km/h)= 18.85 km.

<h3>4. Obtain the total distance.</h3>

The total distance must be given by the addition of all individual distances traveled by the car on each speed:

Total distance= 30.38 km + 19.08 km + 18.85 km= 68.31 km.

5 0
2 years ago
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