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mash [69]
4 years ago
13

at a 200 meter swimming competition bill got a personal record of 45 secomda and time was 5 secomds faster then bill at the comp

etition what was the speed of time for the swimmimg competition
Physics
1 answer:
steposvetlana [31]4 years ago
4 0

Answer:

Average speed of the swimmer is 4.44 m/s

Explanation:

As we know that the speed is the ratio of distance covered over time interval

so here we can say

v = \frac{d}{t}

so we know that

d = 200 m

time taken to complete the trip is

t = 45 s

now we have

v = \frac{200}{45}

v = 4.44 m/s

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2 equal charges, 27 micro Coulomb each, are separated by 5 cm. Find force between those.
padilas [110]

Answer:

The force between charges is  F= 2.624*10^3N.

Explanation:

The Coulomb force F between the two charges q_1 and q_2 separated by distance d is given by the equation

F = k\dfrac{q_1q_2}{d^2}

where k is the coulombs constant, and has the value

k= 9*10^9N\cdot C\cdot m^2.

Now in our case

q_1=q_2=27\mu C =27*10^{-6}C

and

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therefore, the Coulomb force between the charges is

F =( 9*10^9N\cdot C\cdot m^2)*\dfrac{(27*10^{-6}C)(27*10^{-6}C)}{(0.05m)^2}

\boxed{ F= 2.624*10^3N}

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4 years ago
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butalik [34]
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4 years ago
A plane passes over Point A with a velocity of 8000 m/s north. Forty seconds later it passes over Point B at a velocity of 10,00
Airida [17]

Answer:

The planes’ acceleration from A to B is 500m/s^2

Explanation:

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we know that the expression for acceleration is given as

a=(v-u)/t

substituting our given data into the expression for a we have

a=(10000-8000)/40

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The planes’ acceleration from A to B is 500m/s^2

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Answer:

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