Answer
Pressure, P = 1 atm
air density, ρ = 1.3 kg/m³
a) height of the atmosphere when the density is constant
Pressure at sea level = 1 atm = 101300 Pa
we know
P = ρ g h
h = 7951.33 m
height of the atmosphere will be equal to 7951.33 m
b) when air density decreased linearly to zero.
at x = 0 air density = 0
at x= h ρ_l = ρ_sl
assuming density is zero at x - distance
now, Pressure at depth x
integrating both side
now,
h = 15902.67 m
height of the atmosphere is equal to 15902.67 m.
Answer:
Distance between Venus and Sun is 1.0864x10^11 m
Explanation:
Data
T1 (Total time taken by earth to rotate around sun)=365 days
T2 (Total time taken by venus to rotate around sun)=225 days
R1 (Radius b/w Sun and earth)=1.5x10^11m
R2(Distance between Venus and Sun)=?
Solution
Apply Kepler Law
(R2)^3/(R1)^3=(T1)^2/(T2)^2
(R2)^3/(1.5x10^11)^3=(225^2)/(365^2)
R2=1.0864x10^11m
Answer:At the top of the page is a transvers wave
C= crest
B= wavelingth
D= trough
A= amplatud
The next wave is a longitudinal wave
<span>The air sealed between two panes of glass in some windows helps to </span><span>insulate and helps it to keep the warmth or coolness inside.
Hope that helps!
-Chris</span>
Answer:
Three small bones in the mid ear
Explanation:
