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lubasha [3.4K]
3 years ago
14

4. Compare the change in initial and final gravitational force in

Physics
1 answer:
mylen [45]3 years ago
4 0
Gravitational force equals GMm/r^2, where G is constant, M and m are the masses, and r is distance.

For I, if both masses double, the formula becomes G2M2m/r^2, or 4GMm/r^2. Therefore, the gravitational force will quadruple or 4x.

For II, if the distance between the object doubles, the formula becomes GMm/(2r)^2 or GMm/4r^2. In this case, the gravitational force is 1/4x the initial force.
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A car moves in a circular motion and it is subject to a centripetal acceleration of 24 m/s2. If the radius of the circular path
Softa [21]

Answer:

Explanation:

Centripetal acceleration is given by:

a_{c} = v^{2}/r

Thus, centripetal acceleration is inversely proportional to the radius. Thus, when radius will double, the centripetal acceleration will be halved.

3 0
3 years ago
A scientific theory is an explanation that
Ber [7]

Answer:

A theory is a well thought-out clear explanation for observations of the natural environment

Explanation:

<u>A theory is a well thought-out clear explanation for observations of the natural environment</u> that has been created using the scientific process and that brings together many facts and hypotheses. Theories try to explain observations of the natural world that have been made.

I hope this helps explain the answer to your question and why the answer is that answer.

6 0
3 years ago
Tốc độ v của một vật được cho bởi phương trình v = At
ki77a [65]

If <em>v(t)</em> is speed measured in meters per second (m/s), and <em>t</em> is time measured in seconds (s), then the constants <em>A</em> and <em>B</em> in

<em>v(t)</em> = <em>At</em> ³ - <em>Bt</em>

must have units of m/s⁴ and m/s², respectively; otherwise, the equation is dimensionally inconsistent.

[m/s] = <em>A</em> [s]³ - <em>B</em> [s]

[m/s] = [m/s⁴] [s]³ - [m/s²] [s]

[m/s] = [m/s] - [m/s]

[m/s] = [m/s]

5 0
2 years ago
THE WINNER WILL BE AWARDED THE BRAINLIEST PLEASE HELPP
Ivenika [448]

Answer:Correct answer: 15.85 kg·m/s

Explanation:

A 30 kg gun is standing on a frictionless sur-face. The gun fires a 50 g bullet with a muzzlevelocity of 317 m/s.The positive direction is that of the bullet.Calculate the momentum of the bullet im-mediately after the gun was fired.

7 0
3 years ago
A graduated cylinder contains 63.0 mL of water. A piece of gold, which has a density of 19.3 g/ cm3, is added to the water and t
icang [17]

Answer:

29.0 g

Explanation:

The mass of the piece of gold is given by:

m = dV

where

m is the mass

d is the density

V is the volume of the piece of gold

The density of gold is

d = 19.3 g/cm^3

while the volume of the sample is equal to the volume of displaced water, so

V = 64.5 mL - 63.0 mL = 1.5 mL

And since

1 mL = 1 cm^3

the volume is

V = 1.5 cm^3

So the mass of the piece of gold is:

m = (19.3 g/cm^3)(1.5 cm^3)=29.0 g

7 0
3 years ago
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