Answer:
The answer is cosx cot²x ⇒ the first answer
Step-by-step explanation:
∵ cot²x = cos²x/sin²x
∵ secx = 1/cosx
∴ cot²x secx - cosx = (cos²x/sin²x)(1/cosx) - cosx
= (cosx/sin²x) - cosx
Take cosx as a common factor
∴ cosx[(1/sin²x) - 1] ⇒ use L.C.M
∴ cosx[1-sin²x/sin²x]
∵ 1 - sin²x = cos²x
∴ cosx(cos²x/sin²x) = cosx cot²x
Answer: Parallelogram is a kind of quadrilateral where as there are some quadrilaterals (like trapezoid , kite, .. ) that do not satisfy the properties of parallelograms.
Step-by-step explanation:
A quadrilateral is a closed polygon having fours sides.
A parallelogram is a kind of quadrilateral having following properties:
Its opposite sides and opposite angles are equal.
The sum of adjacent angles is 180°.
The diagonal of parallelogram bisect each other.
A Trapezoid is also a quadrilateral . It has only one pair of parallel sides. (The other one are not parallel).
So , all quadrilaterals not parallelograms.
Therefore, parallelograms are always quadrilaterals but quadrilaterals are sometimes parallelograms because parallelogram is a kind of quadrilateral where as there are some quadrilaterals (trapezoid , kite, .. ) ) that do not satisfy the properties of parallelograms.
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These are both simplified and not 9/6, 3/2, 6/4