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krok68 [10]
3 years ago
8

Please answer this correctly without making mistakes

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0
First, multiply 1,127 & 1 by 2
1127 x 2 = 2254
1 x 2 = 2

so that’s 2,254 cups & 2 fl. ounces
since 8 fl. oz. make a cup, and we only have 2, the answer stays as it is

2,254 cups & 2 fl. ounces
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The wrestling team wants to sell pies for a fundraiser. The cafeteria helped out by donating 2 pies. Each pie will be cut into 4
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Answer:

The answer would be 8

Step-by-step explanation:

4x8=32

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Vikentia [17]

Answer:

3x + 11

Step-by-step explanation:

Remember BPEMDAS.

"Three times a number" is saying multiply 3 times a variable; in this case, <em>x</em>. So we have 3x

"The sun of 3x and 11" is saying add our 3x and 11, so: 3x + 11

8 0
3 years ago
Identify the center and radius of the circle (x+4)^2+(y-2)^2=16
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Answer: center is (-4,2) radius is 4

Step-by-step explanation:

Equation of circle

is (X-A)^2+(X-B)^2=r^2

The center Of The circle is (A, B)

The radius Of The circle is r

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7 0
3 years ago
Perpendicular and Angle bisectors​
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3 years ago
A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
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