Answer:
In addition to mathematics, physics and astronomy, Newton also had an interest in alchemy, mysticism, and theology.
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V1 = 30 mL
P1 = 760 torr
P2 = 1520 torr
V2 = ?
applying Boyle's Law
P1*V1 = P2*V2
760 torr * 30 mL = 1520 torr * V2
V2 = 760 torr * 30 mL / 1520 torr
( C ) is correct
Answer:
The solution to this question can be defined as follows:
Explanation:
Please find the attached file for the solution:
Answer:
no. of water molecules associated to each molecule of
= 4
Explanation:
Mass of
before heating = 19.8 g
Mass of
after heating = 12.6 g
Difference in mass of
before and after heating
= 19.8 - 12.6 = 7.2 g
Difference in mass corresponds to mass of water driven out.
Molar mass of water = 18 g/mol
No. of moles of water = 
Mass of
obtained after heating is mass of anhydrous
.
Mass of anhydrous
= 12.6 g
Molar mass of
= 125.9 g/mol
No. of mol of anhydrous
= 
so,
0.1 mol of
have 0.4 mol of water
1 mol of
will have = 
Hence, no. of water molecules associated to each molecule of
= 4