Answer:
1.27 × 10⁵ L
Explanation:
Step 1: Given data
- Initial pressure (P₁): 745 Torr
- Initial volume (V₁): 1.41 × 10⁴ L
- Inital temperature (T₁): 21 °C
- Final pressure (P₂): 63.1 Torr
- Final temperature (T₂): -48 °C
Step 2: Convert the temperatures to the Kelvin scale
We will use the following expression.
K = °C + 273.15
K = 21 °C + 273.15 = 294 K
K = -48 °C + 273.15 = 225 K
Step 3: Calculate the final volume of the balloon
We will use the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
V₂ = P₁ × V₁ × T₂/ T₁ × P₂
V₂ = 745 Torr × 1.41 × 10⁴ L × 225 K/ 294 K × 63.1 Torr
V₂ = 1.27 × 10⁵ L
There are 1825.6 g in a 14.5 moles Lithium permanganate
<h3>
Further explanation</h3>
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass :

moles of Lithium permanganate = 14.5
Lithium permanganate (LiMnO4) MW=125.9 g/mol, so mass :

The one that is not a compound is Cl