Answer:
32.8g/mole
Explanation:
Given parameters:
Mass of sample of gas = 32.8g
Volume = 22.4L
Unknown:
Molecular weight = ?
Solution:
To solve this problem we must understand that at rtp;
1 mole of gas occupies a volume of 22.4L
Number of mole of the gas = 1 mole
Now;
Mass = number of moles x molecular weight
molecular weight =
=
= 32.8g/mole
<u>Answer:</u> The temperature when the volume and pressure has changed is 274 K
<u>Explanation:</u>
To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:

where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
![P_1=760mmHg\\V_1=175L\\T_1=15^oC=[15+273]K=288K\\P_2=640mmHg\\V_2=198L\\T_2=?K](https://tex.z-dn.net/?f=P_1%3D760mmHg%5C%5CV_1%3D175L%5C%5CT_1%3D15%5EoC%3D%5B15%2B273%5DK%3D288K%5C%5CP_2%3D640mmHg%5C%5CV_2%3D198L%5C%5CT_2%3D%3FK)
Putting values in above equation, we get:

Hence, the temperature when the volume and pressure has changed is 274 K
Answer:
c. Waxing crescent
- I hope this helps have a great night
Base on my research and further investigation about the said problem, the possbile answer would be this one.
<span>1. calculate the g of PbO in the 272 g lead crystal (19% PbO)
272 g x 19 /100 = xxx g PbO
xxx g PbO/molecular mass of PbO = moles PbO
2. write and balance the equation of neutralization of PbO and sodium sulfide.
PbO + sodium sulfide -> sodium oxide + lead sulfide
3. Calculate the moles of sodium sulfide that will react with the moles of PbO
4. Convert the moles of sodium sulfide to g of sodium sulfide</span>