10. Capital C and D represent products of chemical reaction, the capital A and B represent reactants, <span>the lower case letter represent coefficients (how many atoms or molecules in chemical reaction).
12. According to </span><span>Le </span>Chatelier's principle (if<span> the concentration is changed, that will shift the equilibrium to the side that would reduce that change in concentration)</span> <span>the equilibrium shift to the left.
13. </span>According to Le Chatelier's principle the equilibrium shift to the right.
14. According to Le Chatelier's principle (<span>When the reaction is </span>exothermic<span>, heat is included as a product)</span> the equilibrium shift to the right.
Answer:
11.9 g of nitrogen monoxide
Explanation:
We'll begin by calculating the number of mole in 6.75 g of NH₃. This can be obtained as follow:
Mass of NH₃ = 6.75 g
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mole of NH₃ =?
Mole = mass /molar mass
Mole of NH₃ = 6.75 / 17
Mole of NH₃ = 0.397 mole
Next, we shall determine the number of mole of NO produced by the reaction of 0.397 mole of NH₃. This can be obtained as follow:
4NH₃ + 5O₂ —> 4NO + 6H₂O
From the balanced equation above,
4 moles of NH₃ reacted to produce 4 moles of NO.
Therefore, 0.397 mole of NH₃ will also react to produce 0.397 mole of NO.
Finally, we shall determine the mass of 0.397 mole of NO. This can be obtained as follow:
Mole of NO = 0.397 mole
Molar mass of NO = 14 + 16 = 30 g/mol
Mass of NO =?
Mass = mole × molar mass
Mass of NO = 0.397 × 30
Mass of NO = 11.9 g
Thus, the mass of NO produced is 11.9 g
H = planks constant
<span>m = mass of the object </span>
<span>u = velocity of the object </span>
<span>h = 6.626 * 10^-34 J/s </span>
<span>the mass of an electron is 9.12*10^-31 kg </span>
<span>10% speed of light = 10% * 3*10^8 = 3*10^7 m/s, i dont have my graphing calc with me right now so i leave the technicalities up to you </span>
First, we convert the moles of each substance into the concentration using the volume of the reactor.
[SO₃] = 0.425/1.5 = 0.283 M
[SO₂] = 0.208 / 1.5 = 0.139 M
[O₂] = 0.208/1.5 = 0.139 M
The equilibrium constant is calculated by:
Kc = [SO₃]² / [O₂][SO₂]²
Kc = (0.283)²/(0.139)(0.139)²
Kc = 29.8 = 2.98 x 10¹
The answer is C
