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riadik2000 [5.3K]
3 years ago
9

Which scenario would result in a population growth of zero? Use this formula: population growth = (birth rate + immigration) – (

death rate + emigration) 12 individuals emigrate, 12 individuals die, 12 individuals are born, 0 individuals immigrate 16 individuals emigrate, 3 individuals die, 13 individuals are born, 0 individuals immigrate 8 individuals emigrate, 0 individuals die, 20 individuals immigrate,12 individuals are born 10 individuals emigrate, 4 individuals die, 14 individuals immigrate, 0 individuals are born
Chemistry
2 answers:
swat323 years ago
8 0

Answer:

12 individuals are born 10 individuals emigrate, 4 individuals die, 14 individuals immigrate, 0 individuals are born

Explanation:

From the formula:

Population growth = (birth rate + immigration) – (death rate + emigration)

                       = (b + i) - (d + e)

<em>For the first option, b = 12, i = 0, d = 12, e = 12</em>

population growth = (12+0) - (12+12) = -12

<em>For the second option: b = 13, i = 0, d = 3, e = 16</em>

population growth = (13+0) - (3+16) = -6

<em>For the third option: b = 12, i = 20, d = 0, e = 8</em>

population growth = (12+20) - (0+8) = 24

<em>For the last option: b = 0, i = 14, d = 4, e = 10</em>

population growth = (0+14) - (4+10) = 0

Hence, the last option is the correct option.

Alex787 [66]3 years ago
5 0

Answer:

d because i got a 100%

Explanation:

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gayaneshka [121]
Hello!

1) What is the limiting reactant?

The chemical equation for this reaction is:

2Al(OH)₃ → Al₂O₃ + 3H₂O

The Limiting Reactant is the one that is in the lowest amount in the reaction and determines how many moles are produced. You can see that in this chemical equation there is only one reactant since this reaction is a decomposition reaction. So, the limiting reactant is Al(OH)₃.

2) How many grams of water are produced?

The chemical equation for this reaction is:

2Al(OH)₃ → Al₂O₃ + 3H₂O

So, we are going to use the following conversion factor to go from grams of Al(OH)₃ to grams of water:

17,8 g Al(OH)_3* \frac{1 mol Al(OH)_3}{78 g Al(OH)_3}* \frac{3 moles H_2O}{2 moles Al(OH)_3}* \frac{18,015 g H_2O}{1 mol H_2O} \\ =6,17 g H_2O

So, 6,17 grams of Water are produced.

Have a nice day!


5 0
4 years ago
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A steel cylinder for scuba diving contains 11.1 L of compressed air. The pressure inside the cylinder is
Juli2301 [7.4K]

Answer:

9.28moles

Explanation:

Given parameters:

volume  = 11.1L

pressure  = 204atm

temperature  = 24°C = 24 + 273  = 297K

Unknown:

Number of moles of air in the cylinder  = ?

Solution:

To solve this problem, we apply the ideal gas equation;

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P is the pressure

V is the volume

n is the number of moles

R is the gas constant  = 0.082atmdm³mol⁻¹K⁻¹

T is the temperature

Now insert the parameters and find n;

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