The rule of three is a way to solve problems of proportionality between three known values and one unknown. <u>This is an operation of finding the fourth term of a proportion knowing the other three</u>.
We can use the rule of three to solve this problem in this way,
500 mL → 6 grams
40 mL → x
This is the same as saying: if in 500 mL there should be 6 grams of agarose powder then in 40 mL how many grams should there be?
So,
→ x = 0.48 g = 480 mg
Then, you need to dissolved 480 mg of agarose powder in 40 mL of water to meet the recipe.
Electrical energy !! i hope this helped :))
The Chlorine and fluorine atoms are the most electronegative.
So, option D and E is correct one.
The atom of a given chemical elements having tendency to attract bonded pair of electron toward itself is called electronegativity. The electronegativity of atoms is affected by both its atomic number and distance at which its valence electrons resides from the charged nucleus.
The electronegativity of the elements is increases on moving left to right in the period of periodic table while decreasing on moving top to bottom in the group of periodic table .
Example:
The elctronegativity of fluorine atom = 3.98
The elctronegativity of chlorine atom =3.16
The elctronegativity of carbon atom = 2.25
The elctronegativity of phosphorus atom = 2.19
The elctronegativity of silicon atom = 2.58
learn more about electronegativity
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Answer:
We need 41.2 L of propane
Explanation:
Step 1: Data given
volume of H2O = 165 L
Step 2: The balanced equation
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
Step 3: Calculate moles of H2O
1 mol = 22.4 L
165 L = 7.37 moles
Step 4: Calculate moles of propane
For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O
For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane
Step 5: Calculate volume of propane
1 mol = 22.4 L
1.84 moles = 41.2 L
We need 41.2 L of propane
Answer:
See explanation
Explanation:
The slope of a graph in which mass was plotted against volume is the density of the object. Density of objects have been measured and recorded in standard handbooks for the purpose of reference. If the density of an unknown substance is measured, it can now be compared with the density of known substances recorded in standard handbooks such as the handbook of physics and chemistry. By so doing, the unknown substance can be identified.
According to standard handbooks, the density of copper is 8.96 g/ml while that of nickel is 8.908 g/ml. If the average slope obtained is around 8.96 g/ml, then the metal is copper and not nickel.
An alternative to this method is to measure the refractive index of the piece of metal and compare the average values observed with the contents of standard handbooks in order to identify the unknown metal.