Calculate the mass of each element in the compound by multiplying its molar mass

The discharge of chromate ions (CrO42-) to sewers or natural waters is of concern because of both its ecological impacts and its

muminat

Answer:

45727g

Explanation:

So, have the overall ionic equation given as the following;

CrO42^- + 3 Fe2^+ + 8 H2O ------> Cr(OH)^3(s) + 3 Fe(OH)^3(s) + 4 H^+.

So, we have (from the question) that the amount or quantity of the waste stream daily = 60m^3/h, and the waste stream daily contains waste stream containing = 4.0 mg/L Cr, and the discharge limit = 0.1 mg/L.

Step one: convert m^3/ h to L/h. Therefore, 60 m^3/h × 1000dm^3 = 60000 L/h .

Step two: Determine or calculate the the value of Cr used up.

The value of Car used up ={ 60,000 × ( 4.0 - 0.1) } ÷ 1000 = 234 g.

Step three: Determine or calculate the mass of Cr(OH)3 and the mass of Fe(OH)3.

The number of moles of Cr = 234/52 = 4.5 moles.

Molar mass of Cr(OH)3 = 103 g/mol and the molar mass of Fe(OH)3 = 106.8 g/mol.

Thus, the mass of Cr(OH)3 = 4.5 × 103 = 463.5 g.

And the mass of Fe(OH)3 = 13.5 × 106.8 = 1441.8 g.

Hence, the total = 463.5 g + 1441.8 g = 1905.3 g.

Step four: Determine or calculate the How much particulate matter would be generated daily.

The amount of the particulate that would be generated daily = 24 × 1905.3 = 45727g.

7 0

3 years ago

An old antacid commercial claimed that each tablet of their product could neutralize 47 times its mass in stomach acid. The acti

butalik [34]

Answer : The number of moles of HCl neutralize is, 0.00824 moles.

Explanation :

The given balanced chemical reaction is:

$NaAl(OH)_2CO_3+4HCl\rightarrow NaCl+AlCl_3+3H_2O+CO_2$

First we have to calculate the moles of $NaAl(OH)_2CO_3$

$\text{Moles of }NaAl(OH)_2CO_3=\frac{\text{Mass of }NaAl(OH)_2CO_3}{\text{Molar mass of }NaAl(OH)_2CO_3}$

Molar mass of $NaAl(OH)_2CO_3$ = 144 g/mol

$\text{Moles of }NaAl(OH)_2CO_3=\frac{0.296g}{144g/mol}=0.00206mol$

Now we have to calculate the moles of HCl.

From the balanced chemical reaction we conclude that,

As, 1 mole of $NaAl(OH)_2CO_3$ react with 4 moles of HCl

So, 0.00206 mole of $NaAl(OH)_2CO_3$ react with $0.00206\times 4=0.00824$ moles of HCl

Thus, the number of moles of HCl neutralize is, 0.00824 moles.

8 0

3 years ago

Which accurately represents these building blocks of matter from the smallest to the largest?

cricket20 [7]

A atom, molecule, element is smallest to largest

7 0

3 years ago

A piece of metal is composed of atoms. Each atom in the metal contains 29 protons. How is the metal classified?

Daniel [21]

Answer:

A transition metal

Explanation:

The metal is classified as a transition metal or transition element.

In particular, this atom is Copper it has an atomic number of 29 which we know by the number of protons.

The number of protons in an atom is the same as the atomic number.

The element can be found in the d-block on the periodic table.
Generally, it is classified as a transition metal.
A neutral atom of this element has 29 electrons.

7 0

3 years ago

What is the chemical composition of bituminous coal?

horsena [70]

Answer: (The composition of a bituminous coal by percentage is roughly: carbon [C], 75–90; hydrogen [H], 4.5–5.5; nitrogen [N], 1–1.5; sulfur [S], 1–2; oxygen[O], 5–20; ash, 2–10; and moisture, 1–10.)

5 0

3 years ago