Type of reaction based on the reactants FeCl3 +K →

Chemistry

1 answer:

strojnjashka [21]2 years ago

3 0

Answer:

complexation

Explanation:

KSCN + FeCl 3 → K + + [FeSCN] 2+ + 3 Cl. This is a complexation reaction: [FeSCN] 2+ is the formed complex.

You might be interested in

(11) Indicate which of the following atomic models best fits the atomic model of

Rzqust [24]

Dnndhdfbbdhdhxbfbdbbds

6 0

3 years ago

Why do atoms move at different speeds depending on whether they are in liquids or solids.

bekas [8.4K]

In a solid the atoms are tightly packed together and vibrate in place, in a liquid the atoms are loosely packed together and can move past each other,

extra: and in a gas the atoms are far apart and move freely and

6 0

2 years ago

Dioxin, produced as a by-product of various industrial chemical processes, is suspected of contributing to the development of ca

Alecsey [184]

Answer:

Explanation:

Why can a signaling molecule cause different responses in different cells? Different cells have membrane receptors that bind to different sides of the signaling molecule. The transduction process is unique to each cell type; to respond to a signal, different cells require only a similar membrane receptor

4 0

3 years ago

Which of the following are not single-displacement reactions?

Goshia [24]

Answer:

$\boxed{\text{B and C }}$

Explanation:

In a single-displacement reaction, one element exchanges partners with another element in a compound.

$\textbf{A. } \rm Fe + 2HCl \longrightarrow FeCl_2 + H_2$

This is a single-displacement reaction, because the element Fe exchanges partners with H in HCl.

$\textbf{B. } \rm KOH + HNO_3 \longrightarrow H_2O + KNO_3$

This is not a single-displacement reaction, because it is a reaction between two compounds.

This is a double displacement reaction in which the K⁺ and H⁺ cations change partners with the anions.

$\textbf{C. } \rm Na_2S + 2HCl \longrightarrow 2NaCl + H_2S$

This is not a single-displacement reaction. It is another double displacement reaction, in which the Na⁺ and H⁺ cations change partners with the anions.

$\textbf{D. } \rm Ca + 2HOH \longrightarrow Ca(OH)_2 + H_2$