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3 years ago

A brick has a mass of 100 G and a volume of 25CM3 what is the density of the brick

Chemistry

1 answer:

kumpel [21]3 years ago

5 0

Answer:

$\boxed {\boxed {\sf 4 \ g/cm^3}}$

Explanation:

We are asked to find the density of a brick. Density is a substance's mass per unit volume. The formula for calculating density is as follows.

$\rho= \frac{m}{v}$

The mass of the brick is 100 grams and the volume is 25 cubic centimeters.

m= 100 g
v= 25 cm³

Substitute the values into the formula.

$\rho= \frac{ 100 \ g}{25 \ cm^3}$

Divide.

$\rho=4 \ g/cm^3$

The density of the brick is 4 grams per cubic centimeter.

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What volume of product is produced when 20.0 Mg of liquid hydrogen reacts with

mihalych1998 [28]

Answer: The volume of product formed is 0.26 L

Explanation:

$\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}$

$\text{Moles of} H_2=\frac{0.02g}{2g/mol}=0.01moles$

$2H_2(l)+O_2(l)\rightarrow 2H_2O(g)$

As $O_2$ is the the excess reagent, $H_2$ is the limiting reagent as it limits the formation of product.

According to stoichiometry :

2 moles of $H_2$ give = 2 moles of $H_2O$

Thus 0.01 moles of $H_2$ will give = $\frac{2}{2}\times 0.01=0.01moles$ of $H_2O$

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 101.325 kPa = 1 atm

V = Volume of gas = ?

n = number of moles = 0.01

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $40^0C=(40+273)K=313K$

$V=\frac{nRT}{P}$

$V=\frac{0.01mol\times 0.0821L atm/K mol\times 313K}{1atm}=0.26L$

Thus the volume of product formed is 0.26 L

8 0

3 years ago

Identify the product formed from the phosphorylation of adp.

yulyashka [42]

Phosphorylation is a process in which addition of phosphoryl group is added. This process explains the presence of the PO₃⁻ in the molecules. One type of phosphorylation is that which is termed as the substrate-level phosphorylation. This is a metabolic reaction that allows or results to the formation of ATP due to the direct transfer of phosphoryl to ADP.

Hence, the answer is ATP.

4 0

3 years ago

Read 2 more answers

Use the following balanced reaction to solve 1-3:

tino4ka555 [31]

Answer:

1.96g H2

Explanation:

P4 = 123.9g/mol

H2 = 2.02g/mol

$\frac{20g P_{4} }{1}$ * $\frac{1 mol P_{4} }{123.9g}$ * $\frac{6 mol H_{2} }{1 mol P_{4} }$ * $\frac{2.02g H_{2} }{1 mol H_{2} }$ = 1.96g H2