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3 years ago

ZnH2 + Cl2 → 2HCI + Zn

Chemistry

1 answer:

Ivahew [28]3 years ago

3 0

Answer:

2 moles H

Explanation:

Your tool of choice here will be the mole ratio that exists between zinc metal,

, and hydrochloric acid,

:HCl

, in the balanced chemical equation.

(s]

HCl

(aq]

→

ZnCl

2(aq]

2(g]

↑

⏐

You're dealing with a single replacement reaction in which zinc displaces the hydrogen from hydrochloric acid. The products of the reaction are aqueous zinc chloride and hydrogen gas.

Now, as you can see from the balance chemical equation, a

mole ratio exists between the two reactants.

This tells you that in order for the reaction to take place, you need to have twice as many moles of hydrochloric acid as you do of zinc metal.

http://people.springfield.k12.or.us/jim.tyser/chemcom/Resources/unit1ans.html

At the same time, you have a

mole ratio between hydrochloric acid and hydrogen gas.

This means that the reaction will always produce half as many moles of hydrogen gas as you have moles of hydrochloric acid.

Since you know that

moles of hydrochloric acid are taking part in the reaction, and assuming that you have enough zinc metal so that it doesn't act as a limiting reagent, you can say that the reaction will produce

moles HCl

⋅

1 mole H

moles HCl

2 moles H

Explanation:

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3 years ago

A 30.0 g sample of a metal was heated in a hot water bath to 80°c. it was then quickly transferred to a coffee-cup calorimeter.

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when the metal is lost heat and the calorimeter of water is gained the heat

and when the heat lost = the heat gained so,

(M*C*ΔT)m = (M*C*ΔT)w

when Mm= mass of the metal = 30 g

Δ Tm = (80-25) = 55 °C

and Mw = mass of water = 100 g

Cw is the specific heat of water = 4.181 J/g.°C

ΔTw = (25-20) = 5 °C

so by substitution:

∴ 30* Cm*55 = 100 * 4.181 * 5

∴Cm (specific heat of metal) = (100*4.181*5)/(30*55)

∴C of metal = 1.267 J/g.°C

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4 years ago

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Explanation:

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4 years ago

5. A gas has a pressure of 310 kPa at 237 degrees C. What will its pressure be at 23 degrees C?)

slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T} =k$