to write 98 as a product of its prime factors we have to first find the prime factors of 98
prime factors are prime numbers by which the given number can be divided by.
98 we have to keep dividing it by prime numbers
98 is an even number so we can first divide by 2
98 / 2 = 49
49 is a multiple of 7 which too is a prime number so we can divide 49 by 7
49/7 = 7
7 can be divided again by 1
7/7 = 1
98 is divisible by 2 and 7
so 98 written as a product of prime factors is
98 = 2 x 7 x 7
For the linear system :
r+t = 20 and 5(r+t) = 150
If you sub in the first equation into the second, you will get: 100 = 150, which is incorrect
It means the system does NOT have solutions.
Answer will be the last choice
Answer:
36
Step-by-step explanation:
![-2[-6(-4+7)]\\\\=(-2)(-6)(3)\\\\=12(3)\\\\=36](https://tex.z-dn.net/?f=-2%5B-6%28-4%2B7%29%5D%5C%5C%5C%5C%3D%28-2%29%28-6%29%283%29%5C%5C%5C%5C%3D12%283%29%5C%5C%5C%5C%3D36)
Answer:
33.493
Step-by-step explanation:
the 33.493(the last 3 is repeated)
