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Tanzania [10]
3 years ago
11

Evaluate 5c+cd when c=1/5 and d = 15

Mathematics
1 answer:
dimaraw [331]3 years ago
5 0

Answer: 4

Step-by-step explanation: Here we're asked to evaluate 5c + cd given that c = 1/5 and d = 15.

So all we have to do is plug our given values for <em>c</em> and <em>d</em> into the problem and simplify from there.

5c would be 5(1/5) + <em>c</em> which is<em> </em>1/5 · <em>d</em> which is 15 so we have (1/5)(15).

So rewriting our problem we have 5(1/5) + (1/5)(15).

Simplifying from here, remember that our order of operations tells us we must first multiply 5(1/5) and (1/5)(15).

So multiplying 5(1/5), the 5 and 5 cross cancel

to 1 and 1 so we have 1 · 1 or 1.

Next we have (1/5)(15) which we can rewrite as

(1/5)(15/1) which is 15/5 or 3.

So we now have 1 + 3 which is 4.

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In parallelogram EFGH, EJ = 6x + 3 and JG = 10x - 5 What is EG?<br>A: 15<br>B: 12<br>C: 25<br>D: 30​
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Step-by-step explanation:

It seems J is the intersection of diagonals.

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<u>It gives us:</u>

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<u>Substitute and solve for x:</u>

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