In parallelogram EFGH, EJ = 6x + 3 and JG = 10x - 5 What is EG?A: 15B: 12C: 25D: 30
2 answers:
Answer:
30
Step-by-step explanation:
We know that
Opposite sides of a parallelogram are equal. I am assuming J as the diagonal.
EJ = JG
=> 6x + 3 = 10x - 5
=> 6x - 10x = -5 - 3
=> -4x = -8
=> x = -8/-4
=> x = 2
Now,
EG = 2EJ
EG = 2(6 × 2 + 3)
EG = 2(12 + 5)
EG = 2(15)
EG = 30
Answer:
Step-by-step explanation:
It seems J is the intersection of diagonals.
We know diagonals of the parallelogram bisect each other.
<u>It gives us:</u>
<u>Substitute and solve for x:</u>
- 6x + 3 = 10x - 5
- 10x - 6x = 3 + 5
- 4x = 8
- x = 2
<u>Find the value of EJ:</u>
<u>Find the value of EG:</u>
Correct choice is D
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