3 years ago

A: h(8)=-67 B: h(8)=-370

Mathematics

2 answers:

noname [10]3 years ago

7 0

h(x) = 5 - 9x

h(8) = 5 - 9(8)

h(8) = 5 - 72

Your answer is h(8) = -67.

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Nezavi [6.7K]3 years ago

5 0

Answer: A

Step-by-step explanation: x=8 so then 5-9x= −67

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Given the function f(x) x^2-2x/x^3 +9x^2-10x Find any holes, vertical asymptotes, and horizontal asymptotes there may be.

yulyashka [42]

Answer:

See below

Step-by-step explanation:

I assume you mean $f(x)=\frac{x^2-2x}{x^3+9x^2-10x}$ :

Holes: Since $f(x)=\frac{x^2-2x}{x^3+9x^2-10x}$ reduces to $f(x)=\frac{x(x-2)}{x(x^2+9x-10)}$ , then there is a hole at $x=0$ as $x$ exists in both the numerator and denominator (however, its limit as x approaches 0 is 1/5).

Vertical Asymptotes: If we further reduce $f(x)=\frac{x(x-2)}{x(x^2+9x-10)}$ to $f(x)=\frac{x-2}{(x+10)(x-1)}$ , then we see that there are vertical asymptotes at $x=-10$ and $x=1$