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MArishka [77]
3 years ago
9

What is the value of x in the figure above? ^^

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
7 0
First solve for the other angles.
You know one angle is 15º.
The one across from it is also 15º since it is a vertical angle to the known 15º angle.
Both of those together gets 30º.
The whole thing is 360º, so just subtract 30 from 360 and divide.
360 - 30 = 330
Do the same for the 15x angle.
The one under/across to it is a vertical angle so is also 15xº.
Now you are left with 30xº = 330.
Just divide now.
330 / 30 = 11
x = 11
15x = 165

Checking your work:
15x = 165
15x = 165
15
15
Those are the angles.
Add those numbers together and make sure it adds up to 360º.
165 + 165 + 15 + 15 = 360
So this is correct.
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Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute
Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so \mu = 35

Variance = 81. The standard deviation is the square root of the variance, so \sigma = \sqrt{81} = 9.

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, z = -0.44 has a pvalue of 0.333. So what is the value of X when z = -0.44.

Z = \frac{X - \mu}{\sigma}

-0.44 = \frac{X - 35}{9}

X - 35 = -3.96

X = 31.04

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

P = P_{1} + P_{2}

P_{1} is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of X = 40.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{40.5 - 35}{9}

Z = 0.61

Z = 0.61 has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if P_{1} = 100% - 72.91% = 27.09% = 0.2709

P_{2} is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

X = 38.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{38.5 - 35}{9}

Z = 0.39

Z = 0.39 has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if P_{1} = 100% - 65.17% = 34.83% = 0.3483

So:

P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

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3 years ago
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Answer: width: 4, length: 16
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