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stich3 [128]
1 year ago
9

Guidelines for the amount of supplementary nitrogen needed to grow winter wheat depend on the amount of nitrogen in the soil​ (a

s determined by a soil​ test), the price of​ fertilizer, and the price of wheat at harvest. Suppose the soil on a particular farm has a nitrogen content of 2 ppm​ (parts per​ million) and acres will be planted in winter wheat. Consider two pricing scenarios.
Case​ A: The price of fertilizer is ​$​/lb., the price of wheat is ​$​/bushel, and the expected yield is ​bushels/acre.
Case​ B: The price of fertilizer is ​$​/lb., the price of wheat is ​$​/bushel, and the expected yield is ​bushels/acre.
In Case​ A, the guidelines recommend adding pounds of nitrogen per​ acre, and in Case​ B, pounds of nitrogen per acre. Assuming all other factors are​ equal, compute and compare the net profits​ (income minus​ expenses) for the two scenarios.
Mathematics
1 answer:
Ierofanga [76]1 year ago
3 0

The net profit or income for case A and case B based on the information will be $9250 and $9500 respectively.

<h3>How to compute the net profit?</h3>

Case A:

Based on the information, the price of fertilizer will be:

= 0.25 × 100 × 50

= $1250

Price of wheat = 3.50 × 50 × 50

= $10500

Net profit = $10500 - $1250

= $9250

Case B:

Price of fertilizer will be:

= 0.50 × 70 × 50

= $1750

Price of wheat = 4.50 × 50 × 50

= $11250

Net profit = $11250 - $1750

= $9500

Therefore, the net profit or income for case A and case B based on the information will be $9250 and $9500 respectively.

Learn more about net income on:

brainly.com/question/15530787

#SPJ1

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Part a)

Answer: 5*sqrt(2pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(50/pi)
r = sqrt(50)/sqrt(pi)
r = (sqrt(50)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(50pi)/pi
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Note: the denominator is technically not able to be rationalized because of the pi there. There is no value we can multiply pi by so that we end up with a rational value. We could try 1/pi, but that will eventually lead back to having pi in the denominator. I think your teacher may have made a typo when s/he wrote "rationalize all denominators"

============================================================

Part b)

Answer: 3*sqrt(3pi)/pi

-----------------------

Work Shown:

r = sqrt(A/pi)
r = sqrt(27/pi)
r = sqrt(27)/sqrt(pi)
r = (sqrt(27)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
r = sqrt(27pi)/pi
r = sqrt(9*3pi)/pi
r = sqrt(9)*sqrt(3pi)/pi
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Note: the same issue comes up as before in part a)

============================================================

Part c)

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-----------------------

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r = sqrt(19)/sqrt(pi)
r = (sqrt(19)*sqrt(pi))/(sqrt(pi)*sqrt(pi))
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