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Sever21 [200]
3 years ago
15

A museum is creating an exhibit about cells. Which type of exhibit would best explain what cells are? A. Display a three-dimensi

onal model of a cell. B. Use a life-size drawing of a cell. C. Put a cell on a poster in the exhibit. D. Set up a microscope so that visitors can view cells.
Chemistry
2 answers:
SpyIntel [72]3 years ago
8 0
Considering you should look and not touch in museums... A.
yan [13]3 years ago
4 0
I think the answer would be set up a microscope so that visitors can view cells so they can learn all about them

Please mark as brainliest answer
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Which of these solutes raises the boiling point of water the most?
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(E) ionic aluminum fluoride (AlF3)
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The percent composition of calcium is ?
DochEvi [55]

Answer: 40.1%

Explanation: The mass of calcium in this compound is equal to 40.1 grams because there's one atom of calcium present and calcium has an atomic mass of 40.1 . The molar mass of the compound is 100.1 grams. Using the handy equation above, we get: Mass percent = 40.1 g Ca⁄100.1 g CaCO3 × 100% = 40.1% Ca.

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3 years ago
PLEASE HELP!!! WILL MARK BRAINLIEST!
fredd [130]

The longest chain of carbons will contain the highest number of carbon atoms.

Explanation:

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5 0
3 years ago
How many moles of chlorine (Cl) atoms are in a sample of 1.72 × 1022 atoms? 0.0286 mol Cl 35.0 mol Cl 1.03 × 1023 mol Cl 1.04 ×
kogti [31]

Given information : Sample of 1.72\times 10^{22} atoms

We need to find the moles of Chlorine in the given sample.

We can say that we need to find moles from the given atoms.

Relation between mole and atom is given by : 1 mole = 6.022\times 10^{23} atoms

Where 6.022\times 10^{23} is Avogadro number.

1.72\times 10^{22} atoms\times \frac{1 mole}{6.022\times 10^{23} atoms}

1.72\times 10^{22}\times \frac{1 mole}{6.022\times 10^{23}}

On solving the above equation , atoms(unit) gets cancelled out and we get 0.0286 mol.

In the given sample the moles of Chlorine (Cl) is 0.0286 mol , so option A is correct.

6 0
3 years ago
In which of the following reactions does a decrease in the volume of the reaction vessel at constant
Black_prince [1.1K]

Answer:

The correct option is: A) 2H₂(g) + O₂(g) → 2H₂O(g)

Explanation:

According to the Le Chatelier's principle, change in the volume of the reaction system causes equilibrium to shift in the direction that reduces the effect of the volume change.

When the <u>volume decreases then the pressure of the reaction vessel increases, then the equilibrium shifts towards the reaction side that produces less number of moles of gas.</u>

<u />

A) 2H₂(g) + O₂(g) → 2H₂O(g)

The number of moles of reactant is 3 and number of moles of product is 2.

<u>Therefore, when volume decreases, the equilibrium shifts towards the product side, thereby </u><em><u>favoring the formation of products.</u></em>

B) NO₂(g) + CO(g) → NO(g) + CO₂(g)

The number of moles of reactant and product both is 2.

<u>Therefore, when the volume decreases, the equilibrium does not shift in any direction.</u>

C) H₂(g) + I₂(g) → 2HI(g)

The number of moles of reactant and product both is 2.

<u>Therefore, when the volume decreases, the equilibrium does not shift in any direction.</u>

D) 2O₃(g) → 3O₂(g)

The number of moles of reactant is 2 and number of moles of product is 3.

<u>Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby </u><em><u>favoring the formation of reactants.</u></em>

E) MgCO₃(s) → MgO(s) + CO₂(g)

The number of moles of reactant is 1 and number of moles of product is 2.

<u>Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby </u><em><u>favoring the formation of reactants.</u></em>

6 0
3 years ago
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