Answer:
Marine life is least affected by the temperature fluctuations of the atmosphere.
Explanation:
The high specific heat capacity of water means that it takes much more energy to raise the temperatures of water by one (1) degree than land. This means that on a hot sunny day, land temperatures would increase dramatically while ocean temperatures would only rise slightly. Conversely, at night, the land cools rapidly while oceans cool slowly hence the temperatures drop slightly.
Moles of ca3(po4)2 = 23.7 / 310.17 = 0.076
moles of (PO4)3- = 0.076 x 2 = 0.152
now, no. of ions = 0.152 x 6.022 x 10^{23}
= 9.2 x 10^{22}
Answer:
Baking soda = No. of atoms are 1 sodium + 1 Hydrogen + 1 carbon + 3 oxygens = 6 atoms per molecule.
Answer:
80.8 g
Explanation:
First, let's write a balanced equation of this reaction
MgO + 2HNO₃ → Mg(NO₃)₂ + H₂O
Now let's convert grams to moles
We gotta find the weight of MgO
24 + 16 = 40 g/mol
12/40 = 0.3 moles of MgO
We can use this to find out how much Magnesium Nitrate will be formed
0.3 x 1 MgO / 1 Mg(NO₃)₂ = 0.3 moles of Magnesium Nitrate formed
Convert moles to grams
Find the weight of Mg(NO₃)₂ but don't forget that 2 subscript acts as a multiplier of whatever is inside that parenthesis.
24 + 14 x 2 + 16 x 3 x 2 = 148 g/mol
148 x 0.3 = 80.8 g
Answer: The concentrations of
at equilibrium is 0.023 M
Explanation:
Moles of
= ![\frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D%5Cfrac%7B10g%7D%7B71g%2Fmol%7D%3D0.14mol)
Volume of solution = 1 L
Initial concentration of
= ![\frac{0.14mol}{1L}=0.14M](https://tex.z-dn.net/?f=%5Cfrac%7B0.14mol%7D%7B1L%7D%3D0.14M)
The given balanced equilibrium reaction is,
![COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)](https://tex.z-dn.net/?f=COCl_2%28g%29%5Crightleftharpoons%20CO%28g%29%2BCl_2%28g%29)
Initial conc. 0.14 M 0 M 0M
At eqm. conc. (0.14-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5Ctimes%20%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Now put all the given values in this expression, we get :
![4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}](https://tex.z-dn.net/?f=4.63%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7Bx%29%5E2%7D%7B%280.14-x%29%7D)
By solving the term 'x', we get :
x = 0.023 M
Thus, the concentrations of
at equilibrium is 0.023 M