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Hitman42 [59]
3 years ago
12

What is the chemistry of acid and base

Chemistry
1 answer:
dexar [7]3 years ago
4 0

Answer:

Of what?

Explanation:

But uhh: An acid is a substance that donates protons or accepts a pair of valence electrons to form a bond. Bases can be thought of as the chemical opposite of acids.

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Answer: It's A

Explanation:

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If each NADHNADH generates 3 ATPATP molecules and each FADH2FADH2 generates 2 ATPATP molecules, calculate the number of ATPATP m
Nadusha1986 [10]

Answer:

128~ATP

Explanation:

The metabolic pathway by which energy can be obtained from a fatty acid is called <u>"beta-oxidation"</u>. In this route, acetyl-Coa is produced by removing <u>2 carbons</u> from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the <u>number of rounds</u> that will take place for an <u>18-carbon fatty</u> acid using the following equation:

Number~of~Rounds=\frac{n}{2}-1

Where "n" is the <u>number of carbons</u>, in this case "18", so:

Number~of~Rounds=\frac{18}{2}-1~=~8

We also have to calculate the amount of Acetyl-Coa produced:

Number~of~Acetyl-Coa=\frac{18}{2}~=~9

Now, we have to keep in mind that in each round in the beta-oxidation we will have the <u>production of 1 FADH_2 and 1 NADH</u>. So, if we have 8 rounds we will have 8 FADH_2 and 8 NADH.

Finally, for the total calculation of ATP. We have to remember the <u>yield for each compound</u>:

-) 1~FADH_2~=~2~ATP

-) 1~NADH~=~3~ATP

-) Acetyl~CoA~=~10~ATP

Now we can do the total calculation:

(8*2)~+~(8*3)~+~(9*10)=130~ATP

We have to <u>subtract</u>  "2 ATP" molecules that correspond to the <u>activation</u> of the fatty acid, so:

130-2=128~ATP

In total, we will have 128 ATP.

I hope it helps!

6 0
3 years ago
How much CaCO3 would have to be decomposed to produce 247 g of CaO
vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

\tt \dfrac{1}{1}\times 4.41=4.41

mass CaCO₃(MW=100 g/mol) :

\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g

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If you need to translate, the answer is
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