All categories

4 years ago

Your mom is making lunch which forces are acting on your mom

Physics

2 answers:

Cerrena [4.2K]4 years ago

8 0

What is she making? Always ask that

mote1985 [20]4 years ago

3 0

Idk I need to answer a question to ask more so thanks bye

You might be interested in

Assume that segment r exerts a force of magnitude t on segment l. what is the magnitude flr of the force exerted on segment r by

mrs_skeptik [129]

If we are talking on the force being exerted by a segment of a rope of lenght R on the right on a point M which is being also pulled from the Left by a segment of rope R as shown in the figure attached. Then we invoke Newton's Third Law:
"Any force exerted by an object (in this case a segment of the rope) also suffers a equal and opposite force".
If we pick $T_R=T$ whis is the tension exerted by the right segment then the left segment will also exert an equal and opposite force so we have that $T_L=-T$

8 0

3 years ago

Write an equation for the nth term of the arithmetic sequence: 64, 78, 92, 106, ...

Anna [14]

If 64 is term #1 of the sequence,
then the general term is
 T(n) = 50 + 14n .

4 0

4 years ago

koban [17]

The question is not well presented.

There is ______ shift in sound frequency for observers towards whom the source is approaching.

Answer:

The gap should be filled with an apparent upward

Explanation:

The Doppler effect (also referred to as the Doppler shift) is the difference in frequency of a wave when related to an observer who has a relative movement to the wave source

The Doppler effect can be observed to occur with all types of waves - most notably water waves, sound waves, and light waves

The Doppler effect describes sound as an effect which is produced from a moving source of wave.

According to the Doppler effect;

When the source of waves in which there is an apparent upward shift in frequency for observers towards whom the source is approaching.

3 0

4 years ago

A 26.0-kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 11.0 m th

frozen [14]

Answer:

18 m/s

Explanation:

Force is given by mass × acceleration

F = ma

a = F/m

For the first 11.0 m, there is no friction. Hence, the constant force is applied fully on the crate. The acceleration is

a = 225/26.0 m/s²

By the equation of motion, v² = u² + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance travelled.

Using the values for the first part of the motion,

v² = 0² + 2 × 8.65 × 11.0

v = 13.8 m/s

This is the initial velocity for the second part of the motion. This part has friction of coefficient 0.20.

The frictional force = 0.20 × weight = 0.20 × 26.0 × 9.8 = 50.96 N

The effective force moving the crate in the second motion = 225 - 50.96 N = 174.04 N

This gives an acceleration of 174.04/26.0 = 6.69 m/s².

Using parameters for the equation of motion, v² = u² + 2as

v² = 13.8² + 2 × 6.69 × 10 = 324.24

v = 18 m/s

8 0

4 years ago

An implanted pacemaker supplies the heart with 72 pulses per minute, each pulse providing 6.0 V for 0.65 ms. The resistance of t

9966 [12]

Answer: a) 0.11 Amp b) 0.000429 Joules c) 0.000514 watt

Explanation:

a)current

I=V/r I=6.0/550 =1.1*10^-2 A

b) energy

E= 1.1*10^-2 x (6.0) x 0.00065s(<-- remember to convert ms to seconds) = 0.000429J

C) Average power

P = (0.000429 x 72) / 60

P = 0.000514 W

6 0

3 years ago