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vivado [14]
3 years ago
9

For question #17, use the following picture:

Physics
1 answer:
Serhud [2]3 years ago
6 0

Explanation:

18. __Double displacement__ 2LiBr + Pb(NO₃)₂ → PbBr₂ + 2LiNO₃

In a double displacement reaction, there is an actual exchange of partners to form new compounds.

 The driving condition for this kind of reaction are:

  • formation of an insoluble compound called precipitate
  • formation of water or any other non-ionizing compound
  • liberation of a gaseous product.

Learn more:

Precipitation reaction brainly.com/question/1870098

19. ___Single displacement___ Fe + 2HCl  → FeCl₂  + H₂

In a single displacement reaction, one substance replaces another.

  • The replacement of a metallic ion in solution by a metal higher in the activity series than the metal in solution falls into this category.
  • The positions of the two elements in the activity series serves as the driving force.

Learn more:

Chemical reactions brainly.com/question/3953793

20. ___Synthesis___ CaO + H₂O  →  Ca(OH)₂

Synthesis is a combination reaction

  • This reaction involves the formation of a single product from two or more reactants.
  • A compound forms from the union of two or more reactants
  • The large and negative heat of formation of the product is the driving force for this reaction.

Learn more:

Synthesis brainly.com/question/2761166

21. ______Decomposition__ NiCl₂   →  Ni + Cl₂

In a decomposition or cracking reaction, two or more product forms from a single reactant.

The breakdown of a compound into its component individual elements or other compounds fall into this category.

  • The driving force for this reaction is the high heat of formation of the compound and the extreme instability of the compound.
  • A stable compound can also be decomposed on heating and applying pressure.

Learn more:

Thermal decomposition brainly.com/question/11181911

#learnwithBrainly

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A 4 kg bowling bowl is sitting on a table 1 meter off the ground. How much potential energy does it have?
il63 [147K]

Answer:

\huge\boxed{\sf P.E. = 39.2\ Joules}

Explanation:

<u>Given Data:</u>

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

<u>Required:</u>

Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = mgh

<u>Solution:</u>

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

\rule[225]{225}{2}

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