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Monica [59]
3 years ago
15

What safety measures can be added to a circuit and how do they work ?

Physics
1 answer:
tankabanditka [31]3 years ago
6 0

Explanation:

1. Avoid water at all times when working

with electricity. Never touch or try repairing

any electrical equipment or circuits with wet

hands. It increases the conductivity of

electric current.

2. Never use equipment with frayed cords,

damaged insulation or broken plugs.

3. If you are working on any receptacle at

your home then always turn off the mains.

It is also a good idea to put up a sign on

the service panel so that nobody turns the

main switch ON by accident.

4. Always use insulated tools while

working.

5. Electrical hazards include exposed

energized parts and unguarded electrical

equipment which may become energized

unexpectedly. Such equipment always

carries warning signs like “Shock Risk”.

Always be observant of such signs and

follow the safety rules established by the

electrical code followed by the country

you’re in.

6. Always use appropriate insulated rubber

gloves and goggles while working on any

branch circuit or any other electrical circuit.

7. Never try repairing energized equipment.

Always check that it is de-energized first by

using a tester. When an electric tester

touches a live or hot wire, the bulb inside

the tester lights up showing that an

electrical current is flowing through the

respective wire. Check all the wires, the

outer metallic covering of the service paneland any other hanging wires with an

electrical tester before proceeding with your work.

8. Never use an aluminium or steel ladder if you are working on any receptacle at height in your home. An electrical surge will ground you and the whole electric current will pass through your body. Use a

bamboo, wooden or a fibreglass ladder

instead.

9. Know the wire code of your country.

10. Always check all your GFCI’s once a

month. A GFCI (Ground Fault Circuit

Interrupter) is a RCD (Residual Current

Device). They have become very common

in modern homes, especially damp areas

like the bathroom and kitchen, as they help avoid electrical shock hazards. It is

designed to disconnect quickly enough to

avoid any injury caused by over current or

short circuit faults.

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A rock is thrown off a 50.0 m high cliff. How fast must the rock leave the cliff top to land on level ground below, 90 m from th
blagie [28]

Answer:

The rock must leave the cliff at a velocity of 28.2 m/s

Explanation:

The position vector of the rock at a time t can be calculated using the following equation:

r = (x0 + v0x · t, y0 + 1/2 · g · t²)

Where:

r = position vector at time t.

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

Please, see the attached figure for a graphical description of the problem. Notice that the origin of the frame of reference is located at the edge of the cliff so that x0 and y0 = 0.

When the rock reaches the ground, the position vector will be (see r1 in the figure):

r1 = (90 m, -50 m)

Then, using the equation of the vector position written above:

90 m = x0 + v0x · t

-50 m = y0 + 1/2 · g · t²

Since x0 and y0 = 0:

90 m = v0x · t

-50 m = 1/2 · g · t²

Let´s use the equation of the y-component of the vector r1 to find the time it takes the rock to reach the ground and with that time we can calculate v0x:

-50 m = 1/2 · g · t²

-50 m = -1/2 · 9.81 m/s² · t²

-50 m / -1/2 · 9.81 m/s² = t²

t = 3.19 s

Now, using the equation of the x-component of r1:

90 m = v0x · t

90 m = v0x · 3.19 s

v0x = 90 m / 3.19 s

v0x = 28.2 m/s

8 0
3 years ago
How do Earth's and Jupiter's orbits compare?
shutvik [7]
Earth is smaller and have 1 moon so it rotates faster than jupiter and it have 6 moons
Also,earth is the earth is the earth and orbits the sun faster than jupiter the 7th

7 0
3 years ago
A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete
lapo4ka [179]

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ F_x=mgSin \theta=ma

⇒ a_x=gSin \theta

       =9.8 \ Sin35^{\circ}

       =5.62 \ m/s^2

(b)

If friction present,

⇒ F_x=mgCos \theta

⇒ F_x=mgSin \theta-\mu_r mgCos \theta

⇒ a=gSin \theta-\mu_rgCos \theta

      =9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}

      =5.46 \ m/s^2

8 0
2 years ago
A hiker hikes south 0.7 km. she then hikes east 2.4 km. what is the magnitude and unit of her displacement from her initial posi
Usimov [2.4K]
If you illustrate the problem, you will somewhat come up with the figure shown. The missing value is the hypotenuse of the right triangle. Using the pythagorean theorems, the value is determined to be

x = √(0.7^2 + 2.4^2)
x = 2.5 km

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7 0
3 years ago
A pendulum has a mass of 3kg and is lifted to a height of .3m. What is the maximum speed of the pendulum
Kryger [21]

Given data

*The given mass of the pendulum is m = 3 kg

*The given height is h = 0.3 m

The formula for the maximum speed of the pendulum is given as

v_{\max }=\sqrt[]{2gh}

*Here g is the acceleration due to the gravity

Substitute the values in the above expression as

\begin{gathered} v_{\max }=\sqrt[]{2\times9.8\times0.3} \\ =2.42\text{ m/s} \end{gathered}

Hence, the maximum speed of the pendulum is 2.42 m/s

7 0
1 year ago
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