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Monica [59]
3 years ago
15

What safety measures can be added to a circuit and how do they work ?

Physics
1 answer:
tankabanditka [31]3 years ago
6 0

Explanation:

1. Avoid water at all times when working

with electricity. Never touch or try repairing

any electrical equipment or circuits with wet

hands. It increases the conductivity of

electric current.

2. Never use equipment with frayed cords,

damaged insulation or broken plugs.

3. If you are working on any receptacle at

your home then always turn off the mains.

It is also a good idea to put up a sign on

the service panel so that nobody turns the

main switch ON by accident.

4. Always use insulated tools while

working.

5. Electrical hazards include exposed

energized parts and unguarded electrical

equipment which may become energized

unexpectedly. Such equipment always

carries warning signs like “Shock Risk”.

Always be observant of such signs and

follow the safety rules established by the

electrical code followed by the country

you’re in.

6. Always use appropriate insulated rubber

gloves and goggles while working on any

branch circuit or any other electrical circuit.

7. Never try repairing energized equipment.

Always check that it is de-energized first by

using a tester. When an electric tester

touches a live or hot wire, the bulb inside

the tester lights up showing that an

electrical current is flowing through the

respective wire. Check all the wires, the

outer metallic covering of the service paneland any other hanging wires with an

electrical tester before proceeding with your work.

8. Never use an aluminium or steel ladder if you are working on any receptacle at height in your home. An electrical surge will ground you and the whole electric current will pass through your body. Use a

bamboo, wooden or a fibreglass ladder

instead.

9. Know the wire code of your country.

10. Always check all your GFCI’s once a

month. A GFCI (Ground Fault Circuit

Interrupter) is a RCD (Residual Current

Device). They have become very common

in modern homes, especially damp areas

like the bathroom and kitchen, as they help avoid electrical shock hazards. It is

designed to disconnect quickly enough to

avoid any injury caused by over current or

short circuit faults.

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An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complet
pickupchik [31]

Answer:

The acceleration due to gravity at Pluto is 0.0597 m/s^2.

Explanation:

Length, L = 1 m

10 oscillations in 257 seconds

Time period, T = 257/10 = 25.7 s

Let the acceleration due to gravity is g.

Use the formula of time period of simple pendulum

T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2

7 0
3 years ago
The force of gravity on Jupiter is much stronger than the force of gravity on earth what is the answer?
Pachacha [2.7K]

This would be true. On Jupiter you would weigh 234 pounds if you were 100 pounds on Earth.

7 0
3 years ago
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What does the REVOLUTION of Earth around the Sun bring us and how long does it take?
olasank [31]

Answer:

takes 365 days and it bring us seasons such as, spring,winter and fall.

7 0
3 years ago
A large cylindrical tank contains 0.750 cubic meters of nitrogen gas at 27 degrees celsius and 1.5 e5 pa absolute pressure. the
k0ka [10]
<span>3.36x10^5 Pascals The ideal gas law is PV=nRT where P = Pressure V = Volume n = number of moles of gas particles R = Ideal gas constant T = Absolute temperature Since n and R will remain constant, let's divide both sides of the equation by T, getting PV=nRT PV/T=nR Since the initial value of PV/T will be equal to the final value of PV/T let's set them equal to each other with the equation P1V1/T1 = P2V2/T2 where P1, V1, T1 = Initial pressure, volume, temperature P2, V2, T2 = Final pressure, volume, temperature Now convert the temperatures to absolute temperature by adding 273.15 to both of them. T1 = 27 + 273.15 = 300.15 T2 = 157 + 273.15 = 430.15 Substitute the known values into the equation 1.5E5*0.75/300.15 = P2*0.48/430.15 And solve for P2 1.5E5*0.75/300.15 = P2*0.48/430.15 430.15 * 1.5E5*0.75/300.15 = P2*0.48 64522500*0.75/300.15 = P2*0.48 48391875/300.15 = P2*0.48 161225.6372 = P2*0.48 161225.6372/0.48 = P2 335886.7441 = P2 Rounding to 3 significant figures gives 3.36x10^5 Pascals. (technically, I should round to 2 significant figures for the result of 3.4x10^5 Pascals, but given the precision of the volumes, I suspect that the extra 0 in the initial pressure was accidentally omitted. It should have been 1.50e5 instead of 1.5e5).</span>
8 0
3 years ago
REMARKS The speed found in part (a) is the same as if the woman fell vertically through a distance of 21.9 m. The result of part
sasho [114]

Answer:

Yes, if the system has friction, the final result is affected by the loss of energy.

Explanation:

The result that you are showing is the conservation of mechanical energy between two points in the upper one, the energy is only potential and the lower one is only kinetic.

In the case of some type of friction, the change in energy between the same points is equal to the work of the friction forces

    W_{fr} = ΔEm

    W_{fr} = Em_{f} -Em₀

As we can see now there is another quantity and for which the final energy is lower and therefore the final speed would be less than what you found in the case without friction.

    Em_{f} =W_{fr} + Em₀

 

Remember that the work of the rubbing force is negative, let's write the work of the rubbing force explicitly, to make it clearer

    ½ m v² = -fr d + mgh

    v = √(-fr d 2/m + 2 gh)

    v = √ (2gh - 2fr d/m)

Now it is clear that there is a decrease in the final body speed.

Consequently, if the system has friction, the final result is affected by the loss of energy.

5 0
3 years ago
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