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Monica [59]
3 years ago
15

What safety measures can be added to a circuit and how do they work ?

Physics
1 answer:
tankabanditka [31]3 years ago
6 0

Explanation:

1. Avoid water at all times when working

with electricity. Never touch or try repairing

any electrical equipment or circuits with wet

hands. It increases the conductivity of

electric current.

2. Never use equipment with frayed cords,

damaged insulation or broken plugs.

3. If you are working on any receptacle at

your home then always turn off the mains.

It is also a good idea to put up a sign on

the service panel so that nobody turns the

main switch ON by accident.

4. Always use insulated tools while

working.

5. Electrical hazards include exposed

energized parts and unguarded electrical

equipment which may become energized

unexpectedly. Such equipment always

carries warning signs like “Shock Risk”.

Always be observant of such signs and

follow the safety rules established by the

electrical code followed by the country

you’re in.

6. Always use appropriate insulated rubber

gloves and goggles while working on any

branch circuit or any other electrical circuit.

7. Never try repairing energized equipment.

Always check that it is de-energized first by

using a tester. When an electric tester

touches a live or hot wire, the bulb inside

the tester lights up showing that an

electrical current is flowing through the

respective wire. Check all the wires, the

outer metallic covering of the service paneland any other hanging wires with an

electrical tester before proceeding with your work.

8. Never use an aluminium or steel ladder if you are working on any receptacle at height in your home. An electrical surge will ground you and the whole electric current will pass through your body. Use a

bamboo, wooden or a fibreglass ladder

instead.

9. Know the wire code of your country.

10. Always check all your GFCI’s once a

month. A GFCI (Ground Fault Circuit

Interrupter) is a RCD (Residual Current

Device). They have become very common

in modern homes, especially damp areas

like the bathroom and kitchen, as they help avoid electrical shock hazards. It is

designed to disconnect quickly enough to

avoid any injury caused by over current or

short circuit faults.

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How long will it take to travel 200.000 m [N] traveling 10 m/s [N]?
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yuradex [85]

Answer : The values of \Delta H^o,\Delta S^o\text{ and }\Delta G^o are 62.2kJ,132.67J/K\text{ and }22.66kJ respectively.

Explanation :

The given balanced chemical reaction is,

2Ag_2O(s)\rightarrow 4Ag(s)+O_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{product}

\Delta H^o=[n_{Ag}\times \Delta H_f^0_{(Ag)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]-[n_{Ag_2O}\times \Delta H_f^0_{(Ag_2O)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[4mole\times (0kJ/mol)+1mole\times (0kJ/mol)}]-[2mole\times (-31.1kJ/mol)]

\Delta H^o=62.2kJ=62200J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{product}

\Delta S^o=[n_{Ag}\times \Delta S_f^0_{(Ag)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]-[n_{Ag_2O}\times \Delta S_f^0_{(Ag_2O)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[4mole\times (42.55J/K.mole)+1mole\times (205.07J/K.mole)}]-[2mole\times (121.3J/K.mole)]

\Delta S^o=132.67J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 298 K.

\Delta G^o=(62200J)-(298K\times 132.67J/K)

\Delta G^o=22664.34J=22.66kJ

Therefore, the values of \Delta H^o,\Delta S^o\text{ and }\Delta G^o are 62.2kJ,132.67J/K\text{ and }22.66kJ respectively.

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3 years ago
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