An example is free fall ,
Answer:
The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.
hmax = 5740.48 m
Explanation:
This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.
V₀ = 420m/s and θ₀ = 53.0°
So, when the cannonball is fired it has horizontal and vertical components:
V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s
V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s
When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:
Vy = V₀y - g tₐ = 0
tₐ = V₀y/g
tₐ = (335.43m/s)/(9.8m/s²) = 34.23s
Then, the maximum height is reached in the instant tₐ = 34.23s:
h = V₀y tₐ - 1/2g tₐ²
hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²
hmax = 11481.77m - 5741.29m
hmax = 5740.48m
The fraction of the tensile strength which is the stress on the femur is 1.4%.
<h3>What is Tensile strength?</h3>
This is defined as the amount of load or stress that a material can handle before it stretches and breaks.
The femur which is located in the thigh is the largest bone in the body and it exerts a fraction of 1.4% tensile strength through the stress encountered on the femur when the man stands with one leg.
Read more about Tensile strength here brainly.com/question/25748369
Answer:
1.127,56,000m
2. 347,600,000
3. 384,000
4. 200000000
5. 16,000,000cm
6. 36,000,000cm
7. 125,000m long, 400m deep, 1,500m wide
8. 11.18km/sec
9. 5,400,000
10. 2g
11. 1,200 mg to 2700 mg
12. 158000 kg
13. 450000000 mg
14. 23,000g to 90,000g
15. 40,000 ML
16. 1,000 ML
17. 26,600 KL
18. 1,558,000 L
19. 60 ML
20. 0.947
