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Ainat [17]
3 years ago
15

Which energy graph represents the nonspontaneous transition of graphite into diamond?

Chemistry
1 answer:
Vanyuwa [196]3 years ago
8 0

Is that what you have?

Which energy graph represents the nonspontaneous transition of graphite into diamond?

-A graph with Reaction progression on the horizontal axis and energy on the vertical axis. A line starts low on the vertical axis, runs briefly parallel to the horizontal axis, slopes up sharply, curves down a short distance, and levels out.

-A graph with Reaction progression on the horizontal axis and energy on the vertical axis. A line starts midway up the vertical axis, runs briefly parallel to the horizontal axis, slopes up sharply, curves down sharply, and levels out below the initial starting point.

-A graph with Reaction progression on the horizontal axis and energy on the vertical axis. A line starts midway up the vertical axis, runs briefly parallel to the horizontal axis, slopes up a small amount, then curves down to level out below the initial starting point.

-A graph with Reaction progression on the horizontal axis and energy on the vertical axis. A line starts midway up the vertical axis, runs briefly parallel to the horizontal axis, slopes up a moderate amount, then curves down sharply to level out below the initial starting point.

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Molecular iodine, I2(g), dissociates into iodine atoms at 625 K with a first-order rate constant of 0.271 s−1 .
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The correct is this because they said
4 0
2 years ago
Deep sea divers use a mixture of helium and oxygen to breathe. Assume that a diver is going to a depth of 150 feet where the tot
Svetlanka [38]

Answer:

4.525% is the percentage by volume of oxygen in the gas mixture.

Explanation:

Total pressure of the mixture = p = 4.42 atm

Partial pressure of the oxygen = p_1=0.20 atm

Partial pressure of the helium = p_2

p_1=p\times \chi_1 (Dalton law of partial pressure)

0.20 atm=4.42 atm\times \chi_1

\chi_1=\frac{0.20 atm}{4.42 atm}=0.04525

\chi_2=1-\chi_1=1-0.04525=0.95475

chi_1+chi_2=1

n_1=0.04525 mol,n_2=0.95475 mol

According Avogadro law:

Moles\propto Volume (At temperature and pressure)

Volume occupied by oxygen gas  =V_1

Total moles of gases = n = 1 mol

Total Volume of the gases = V

\frac{n_1}{V_1}=\frac{n}{V}

\frac{V_1}{V}=\frac{n_1}{n}=\frac{0.04525 mol}{1 mol}

Percent by volume of oxygen in the gas mixture:

\frac{V_1}{V}\times 100=\frac{0.04525 mol}{1 mol}\times 100=4.525\%

6 0
3 years ago
Name the functional group in the<br> following molecule:
Anna71 [15]

Answer:

B. Aromatic

Explanation:

Functional groups are groups that differentiate a specific organic compound from others. A functional group determines the chemical property of the compound that possesses it.

For example, just like alkene and alcohol functional groups have characteristics double bond (=) and hydroxyl (OH) group respectively, the image in the attachment of this question has a BENZENE RING at the core of its structure, hence, the organic compound can be regarded to have an AROMATIC FUNCTIONAL GROUP.

4 0
3 years ago
Calculate the molar concentration of the Br⁻ ions in 0.51 M MgBr2(aq), assuming that the dissolved substance dissociates complet
Y_Kistochka [10]
MgBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of MgBr2 that dissolves.
MgBr2(s) --> Mg+(aq) + 2 Br⁻(aq)
            [Br⁻] = 0.51 mol MgBr2/1L × 2 mol Br⁻ / 1 mol MgBr2 = 1.0 M
The answer to this question is [Br⁻] = 1.0 M
6 0
3 years ago
Whay is life process? give any four example​
AlladinOne [14]

Answer:

The basic essential activities performed by an organism to withstand its life are called as life processes. These include nutrition, respiration, circulation, excretion and reproduction. Organisms obtain energy from food to perform these life processes which are essential for survival.

6 0
3 years ago
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