Answer:
Yes
Step-by-step explanation:
In any triangle, the sum of any two sides must be larger than the third side. To test this, we only actually need to pick the two shorter sides. In this case, the following inequality is true:
![17+37>53,\\54>53,\\\text{True}\:\checkmark](https://tex.z-dn.net/?f=17%2B37%3E53%2C%5C%5C54%3E53%2C%5C%5C%5Ctext%7BTrue%7D%5C%3A%5Ccheckmark)
Answer:
160 sq. uits
Step-by-step explanation:
160 sq. uits é a resposta
Answer:
D
Step-by-step explanation:
-2, 1 is not a point in the square but - 2, 2 is so the answer should be D -2,1
If my answer helped, kindly mark me as the brainliest!!
Answer:
perimeter-
perimeter outer rectangle = 2 (l+b)
=2×8+9
= 2×17
2×17 =34 cm sq.
perimeter of inner rectangle = 2 (l+b)
= 2×5+3
=2× 8
= 16 cm sq.
perimeter of shaded portion= 34 - 16
= 18 cm sq.
area-
<em>area</em><em> </em><em>of</em><em> </em><em> </em><em>inner</em><em> </em> rectangle =l×b
l×b = 3×5
3×5=15
15 cm sq.
area of outer rectangle =l×b
l×b= 9×8
9×8= 72
72 cm sq.
area of shaded portion = 72 -15 =57 cm sq.
hey there! In second method i have done first area of inner rectangle but you have to do first area of outer rectangle...
hope it helps you....