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ra1l [238]
3 years ago
11

The bear population increases at a rate of 3% each year. There are 1462 bears this year. How many bears will there be in 10 year

s?
Mathematics
2 answers:
lianna [129]3 years ago
5 0
I did (3% x 1462= 43.86) then i took (43.86 x 10= 438.6) then i just took (438.6 + 1462= 1900.6) My answer- 1900 Let me know if its corect 
Anika [276]3 years ago
3 0
1462 * .03 = 43.86
43.86 * 10 =438.6
1462 + 438.6 = 1900.6 bears

Answer 1900.6 (if it says round to nearest number put 1901).
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Wirk out the values of 5x-2y when x=-2 and y = -2
elena-s [515]

Step-by-step explanation:

5x - 2y

5(-2) - 2(-2)

-10 + 4

= - 6

3 0
2 years ago
Plz asap 1. (5 points) What is the value of x? Show all of your work. Round your answer to the nearest tenth.
nalin [4]

Answer:

X = 20.6 inches

Step-by-step explanation:

Pythagorean Theorem: A^{2} =B^{2} +C^{2}

A = 41.2 in, while B = 35.7 in and we are solving for C.

41.2^{2} = 35.7^{2} +C^{2}

1697.44 = 1274.49 + C^{2}

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422.95 = C^{2}

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3 0
3 years ago
In a class of 30 students (x+10) study algebra, (10x+3) study statistics, 4 study both algebra and statistics. 2x study only alg
Vladimir [108]

Answer:

1. The Venn diagrams are attached

2. When the statistics students number = 10·x + 3, we have;

The number of students that study

a. Algebra = 128/11

b. Statistic = 213/11

When the statistics students number = 2·x + 3, we have;

The number of students that study

a. Algebra = 16

b. Statistic = 15

Step-by-step explanation:

The parameters given are;

Total number of students = 30

Number of students that study algebra n(A) = x + 10

Number of students that study statistics n(B) = 10·x + 3

Number of student that study both algebra and statistics n(A∩B) = 4

Number of student that study only algebra n(A\B) = 2·x

Number of students that study neither algebra or statistics n(A∪B)' = 3

Therefore;

The number of students that study either algebra or statistics = n(A∪B)

From set theory we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 10·x + 3 - 4 = 27

11·x+13 = 27 + 4 = 31

11·x = 18

x = 18/11

The number of students that study

a. Algebra

n(A) = 18/11 + 10 = 128/11

b. Statistic

n(B) = 213/11

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11

However, assuming n(B) = (2·x + 3), we have;

n(A∪B) = n(A) + n(B) - n(A∩B)

n(A∪B) = 30 - 3 = 27

Therefore, we have;

n(A∪B) = x + 10 + 2·x + 3 - 4 = 27

2·x+3 + x + 10= 27 + 4 = 31

3·x = 18

x = 6

Therefore, the number of students that study

a. Algebra

n(A) = 16

b. Statistics

n(B) = 15

Hence, we have;

n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12

Similarly, we have;

n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11

The Venn diagrams can be presented as follows;

6 0
2 years ago
In an orienteering competition, Jada walks 70 degrees north of west for 200 meters. She then walks due east for 90 meters. How f
soldi70 [24.7K]
The distance Jada is from starting point will be found using the cosine formula:
c²=a²+b²-2abCos C
a=200, b=90, C=70°
thus plugging in our values we get:
c²=200²+90²-2×200×90×cos70
c²=40000+8100-36000(0.3420)
c²=35788
hence
c=189.1772 m'
therefore the distance Jada is from the starting point is 189.1772 m
4 0
3 years ago
Read 2 more answers
Ok help it’s for a grade I will give Brainly if right
pishuonlain [190]

Answer: 15h^2 + 26h -21

Step-by-step explanation:

Use the foil method. Multiply in this order

First, 5h*3h= 15h^2

outer, 5h*7 = 35h

inner, -3*3h= -9h

last, -3*7= -21

Now add them all together

15h^2 + 35h + -9h + -21

Combine like terms

15h^2 + 26h -21

5 0
3 years ago
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