25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.
The equation of the reaction is;
NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)
We can use the titration formula;
CAVA/CBVB = NA/NB
CA= concentration of acid
VA = volume of acid
CB = concentration of base
VB = volume of base
NA = number of moles of acid
NB = number of moles of base
CB = 0.010 M
VB = 50.0 ml
CA = 0.50 M
VA = ?
NA = 1
NB = 1
Substituting values;
CAVANB = CBVBNA
VA = 0.010 × 50.0 × 1/ 0.50 × 1
VA = 1 ml
Since the total volume of acid used is 1 ml and each drop contains 0.040 ml
The number of drops required is 1ml/0.040 ml = 25 drops
Learn more: brainly.com/question/1527403
Lead is a toxic metal that affects the central nervous system. A Pb-contaminated water sample contains 0.0011% Pb by mass. 13.6 × 10³ ml water contains 150 mg of Pb.
<h3>How to calculate the mass of solution ? </h3>
Given percentage of Pb present in the sample solution is 0.0011%
That means 0.0011 grams of Pb present in the 100g of solution.
So,
= 
= 13.6 × 10³ g water
<h3>What is Density ? </h3>
The mass per unit volume is called density. Density is represented as D or ρ.
It is expressed as:

where,
ρ = Density
m = mass of the object
V = Volume of object
Now put the value in above expression we get


V = 13.6 × 10³ ml
Thus from the above conclusion we can say that Lead is a toxic metal that affects the central nervous system. A Pb-contaminated water sample contains 0.0011% Pb by mass. 13.6 × 10³ ml water contains 150 mg of Pb.
Learn more about the Density here: brainly.com/question/1354972
#SPJ4
Answer:
The answer to your question is 1.25 moles of C
Explanation:
Reaction
5C + 2SO₂ ⇒ CS₂ + 4CO
Check that the reaction is balanced
Reactant Element Product
5 C 5
2 S 2
4 O 4
Use proportions to find the moles of C needed.
5 moles of C ----------------- 2 moles of SO₂
x moles of C ---------------- 0.500 moles of SO₂
x = (0.500 x 5) / 2
x = 1.25 moles of C
I’m pretty sure the answer is false
Answer: dinosaur chicken nuggets
Explanation: REEEEEEEEE