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mihalych1998 [28]
2 years ago
7

One major problem with wind and solar energy is that they are conditional. Explain how hydroelectric pumped storage could be use

d to eliminate this obstacle?
please help me!​
Chemistry
1 answer:
dangina [55]2 years ago
5 0

Answer:

The wind energy and solar energy have their own benefits when producing electricity but one of their major drawbacks is that both these energy form depends on the environmental conditions and cannot be stored.

On the other hand, in hydroelectric pumped storage, water is stored in the form of gravitational potential energy. If not enough water is there to produce electricity, then this stored water can be run over turbines to produce electricity. Hence, this is one benefit of hydroelectric pumped storage over wind and solar energy.

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Difference between---<br> soap and detergent
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Excerpt from textbook

8 0
2 years ago
If 63.8 grams of aluminum metal (Al) react with 72.3 grams of sulfur (S) in a synthesis reaction, how many grams of the excess r
Jobisdone [24]

Answer:

23.2 g of Al will be left over when the reaction is complete

Explanation:

2Al  +  3S  → Al₂S₃

1 mol of Al = 26.98 g

1 mol of S = 32.06 g

Mole = Mass / Molar mass

63.8 g/ 26.98 g/m = 2.36 mole of Al

72.3 g / 32.06 g/m = 2.25 mole of S

2 mole of Aluminun react with 3 mole of sulfur

2.36 mole of Al react with (2.36 .3)/2 = 3.54 m of S

As I have 2.25 mole of S, and I need 3.54 S, is my limiting reagent so the limiting in excess is the Al.

3 mole of S react with 2 mole of Al

2.25 mole of S react with (2.25 m . 2)/3 = 1.50 mole

I need 1.50 mole of Al and I have 2.36, that's why the Al is in excess.

2.36 mole of Al - 1.50 mole of Al = 0.86 mole

This is the quantity of Al without reaction.

Molar mass . mole = Mass →  26.98 g/m . 0.86 m = 23.2 g

7 0
3 years ago
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4 0
2 years ago
How many moles of ammonia, NH,, are contained in<br><br> 6.21 x 1024 molecules of ammonia?
ankoles [38]

Answer:

10.32 moles of ammonia NH₃

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 6.21×10²⁴ molecules

Number of mole of NH₃ =?

The number of mole of NH₃ can be obtained as follow:

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole

Therefore,

6.21×10²⁴ molecules = 6.21×10²⁴ / 6.02×10²³

6.21×10²⁴ molecules = 10.32 moles

Thus, 6.21×10²⁴ molecules contains 10.32 moles of ammonia NH₃

6 0
2 years ago
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