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Rufina [12.5K]
3 years ago
11

A sample of gas has a volume of 2.36 L at a temperature of 53.00 °C. The gas sample is heated to a temperature of 139.00 °C (ass

ume pressure and amount of gas are held constant). Predict whether the new volume is greater or less than the original volume, and calculate the new volume.
Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
5 0

Answer:

The volume increases because the temperature increases and is 2.98L

Explanation:

Charles's law states that the volume of a gas is directely proportional to its temperature. That means if a gas is heated, its volume will increase and vice versa. The equation is:

V₁/T₁ = V₂/T₂

<em>Where V is volume and T is absolute temperature of 1, initial state, and 2, final state of the gas.</em>

In the problem, the gas is heated, from 53.00°C (53.00 + 273.15 = 326.15K) to 139.00°C (139.00 + 273.15 = 412.15K).

Replacing in the Charles's law equation:

2.36L / 326.15K= V₂/412.15K

<h3>2.98L = V₂</h3>

<em />

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Two solutions, initially at 24.60 °C, are mixed in a coffee cup calorimeter (Ccal = 15.5 J/°C). When a 100.0 mL volume of 0.100
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Answer:

ΔH = -59.6kJ/mol

Explanation:

The reaction that occurs between Ag⁺ and Cl⁻ ions is:

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Cl⁻: 0.100L * (0.200mol / L) 0 0.02 moles

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To find heat released we must use coffe cup calorimeter equation:

Q = C*m*ΔT

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The calorimeter absorbs:

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Thus, when 0.01 moles reacts, 585.2J + 10.85  = 596.05J are released (Heat released is heat abosrbed by calorimeter + Heat absorbed by water) and ΔH is:

ΔH = 596.05J / 0.01 moles =

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<em>As heat is released, ΔH < 0.</em>

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