Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
Find the mode of this data set:<br>
31, 30, 32, 31, 30, 31, 32,<br>
33, 30, 31, 31, 30, 32
MariettaO [177]
Answer:
31 is the mode of the data as it appears 5 times
Answer:
See explanation
Step-by-step explanation:
A. Gasoline fill-up fee = $4.50
Cost per hour = $40
Average cost = C
Number of hours the scootcar is rented = h
Cost per h hours = $40h
Total cost = $40h + $4.50
Hence,
C = 40h+4.5
B. To plot the graph of the function, find h- and C- intercepts.
When h = 0, then C = 4.5, and we have point (0,4.5)
When C = 0, then 0 = 40h + 4.5, h = -45/400 = -0.1125, and we have point (-0.1125,0)
Plot these two points and connect them with a straight line.
Graph is attached, but you should take only that part of the graph that corresponds to points with h > 0, because the number of hours cannot be negative